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Zinaida [17]
3 years ago
14

Which of the following wavelengths have the highest frequency? Group of answer choices a.infrared waves b. radio waves c.microwa

ves d.visible light
Physics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

b...radio waves answer

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A raging bull of mass 700 kg runs at 36 km/h .How much kinetic energy does it have ?
Ipatiy [6.2K]

Answer:

Use equation for kinetic energy: Ek=mV²/2

m=700 kg

V=10m/s

Ek=700kg*100m²7s²/2

Ek=35000 J=35kJ

Explanation:

Hope this helps you

Do mark me as brainliest

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3 years ago
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the amplitude of the wave is which of the following A. Resonance B. Reflection C. Energy D. Magnitude
OLga [1]
D.Magnitude is the answer
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What is the relative size and composition of the universe, a galaxy, and a solar system? Is the universe endless?
vichka [17]
Yas, the universe is endless/infinte
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3 years ago
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You pull straight up on the string of a yo-yo with a force 0.35 N, and while your hand is moving up a distance 0.16 m, the yo-yo
jarptica [38.1K]

Answer:

a) 0.138J

b) 3.58m/S

c) (1.52J)(I)

Explanation:

a) to find the increase in the translational kinetic energy you can use the relation

\Delta E_k=W=W_g-W_p

where Wp is the work done by the person and Wg is the work done by the gravitational force

By replacing Wp=Fh1 and Wg=mgh2, being h1 the distance of the motion of the hand and h2 the distance of the yo-yo, m is the mass of the yo-yo, then you obtain:

Wp=(0.35N)(0.16m)=0.056J\\\\Wg=(0.062kg)(9.8\frac{m}{s^2})(0.32m)=0.19J\\\\\Delta E_k=W=0.19J-0.056J=0.138J

the change in the translational kinetic energy is 0.138J

b) the new speed of the yo-yo is obtained by using the previous result and the formula for the kinetic energy of an object:

\Delta E_k=\frac{1}{2}mv_f^2-\frac{1}{2}mv_o^2

where vf is the final speed, vo is the initial speed. By doing vf the subject of the formula and replacing you get:

v_f=\sqrt{\frac{2}{m}}\sqrt{\Delta E_k+(1/2)mv_o^2}\\\\v_f=\sqrt{\frac{2}{0.062kg}}\sqrt{0.138J+1/2(0.062kg)(2.9m/s)^2}=3.58\frac{m}{s}

the new speed is 3.58m/s

c) in this case what you can compute is the quotient between the initial rotational energy and the final rotational energy

\frac{E_{fr}}{E_{fr}}=\frac{1/2I\omega_f^2}{1/2I\omega_o^2}=\frac{\omega_f^2}{\omega_o^2}\\\\\omega_f=\frac{v_f}{r}\\\\\omega_o=\frac{v_o}{r}\\\\\frac{E_{fr}}{E_{fr}}=\frac{v_f^2}{v_o^2}=\frac{(3.58m/s)}{(2.9m/s)^2}=1.52J

hence, the change in Er is about 1.52J times the initial rotational energy

5 0
3 years ago
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A periodic wave with wavelength 2m has a speed of 4m/s. What is the waves frequency?.
Gekata [30.6K]

The wave frequency is 2 Hz.

What is wave frequency ?

The number of waves that pass through a fixed point in a given amount of time is referred to as the wave frequency. The hertz is the SI unit for wave frequency (Hz).

f = v / w

where,

f = frequency\\v = speed \\w = wavelength

Given,

v = 4 m/s, w = 2 m

f = 4/2 \\f = 2 Hz\\

The waves frequency is 2 Hz.

To know more about wave frequency,check out:

brainly.com/question/15830195

#SPJ4

5 0
1 year ago
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