The equation for calculating a mass is as follows:
m=n×M
Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:
n(H2SO4)=N/NA
n(H2SO4)= 1.7×10²³ / 6 × 10²³
n(H2SO4)= 0.3 mole
Now we can calculate a mass of H2SO4:
m(H2SO4) = n×M = 0.3 × 98 = 27.8 g
The volume of the nitrous oxide gas is 1729.3 Liters
<h3>What is the number of moles of gas present in 3.40 kg of nitrous oxide?</h3>
The number of moles of gas present in 3.40 kg of nitrous oxide is determined from the formula below:
Numbers of moles = mass/molar mass
the mass of nitrous oxide = 3.40 kg or 3400 g
the molar mass of nitrous oxide = 44.013 g/mol
Moles of gas = 3400 / 44.013
Moles of gas = 77.25 moles
Using the ideal gas equation to determine the volume of the gas:
PV= nRT
V = nRT/P
where;
- V is the volume of gas
- n is the number of moles of gas
- R is molar Gas constant = 0.082 L.atm/mol/K
- T is the temperature of the gas
V = 77.25 * 0.082 * 273 / 1
The volume of the gas = 1729.3 Liters
Learn more about ideal gas equation at: brainly.com/question/20212888
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As you go down the periodic table, electronegativity decreases. As you go across the pt, it increases. It is the same trend as ionization energy.
Answer : The correct option is, (E) 6 moles.
Explanation : Given,
Moles of nitrogen = 2 moles
The given balanced chemical reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of nitrogen gas react with 3 moles of hydrogen gas
So, 2 mole of nitrogen gas react with 
moles of hydrogen gas
Therefore, the number of moles of hydrogen gas needed to react with 2 moles of nitrogen gas is, 6 moles.
