Answer:
the third one
Step-by-step explanation:
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
To solve this problem, we are going to set up an equation. Let the number that we are trying to find be represented by the variable x. If we plug in the numbers that we know, we get the following equation:
3x/4 = 24
To simplify this equation, we need to multiply both sides by 4, to begin getting the x alone on the left side of the equation.
3x = 96
Finally, we need to divide both sides by 3, to get rid of the coefficient that is being multiplied to x.
x = 32
Therefore, the number that you are trying to find is 32.
The answer is -10x^3+23x^2-24x+18
(2x - 5) (5x - 10)
Use FOIL
10x² - 20x - 25x + 50
10x² - 45x + 50
5( 2x² - 9x + 10)
2x -5
x -2
5(2x - 5)(x -2)
make each equal to 0
2x - 5 = 0
x - 2 = 0
2x - 5 = 0 x - 2 = 0
2x - 5 (+5) = 0 x - 2 (+2) = 0 (+2)
2x = 5 x = 2
x = 5/2
x = 5/2 , 2
hope this helps
