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1 answer:
Answer:
A. 1.02 moles .
Explanation:
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In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:
Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:
Therefore, the correct answer is A. 1.02 moles
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When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>
Equation :
MOH (s) ⇄ M⁺ (aq) ₊ OH⁻(aq)
K = [M⁺] [OH⁻]
K = 1.39×10⁻¹² and [M⁺] = 0.001M
∴ 1.39×10⁻¹² = (0.001M) [OH⁻]
[OH⁻] = 1.004×10⁻¹⁹M
pOH = -log [OH⁻] = 11.9
pH = 14 - pOH
= 14 - 11.9
<u>pH = 2.1</u>
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