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MariettaO [177]
2 years ago
8

How many subshells in 4s

Chemistry
1 answer:
anyanavicka [17]2 years ago
3 0

Answer:

hhjkjggghjjjjjj

Explanation:

vbjjkkkkkkkj

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What is the balanced equation for the decomposition of calcium oxide?
aleksklad [387]
CaO
does not decompose easily.
Explanation:
Calcium oxide is chemically and physically stable at high temperatures.
Maybe you are looking for the decomposition of
CaCO
3
to
CaO
?
That would be
CaCO
3
→
CaO
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CO
2
3 0
3 years ago
What happens to iron in a bolt as the bolt rusts?
Nataly [62]

Answer:

Rusting of iron is an oxidation-reduction reaction in which iron losses electrons to oxygen atom. Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Explanation:

8 0
3 years ago
Read 2 more answers
Ffg full form<br>gti<br>ccc<br>​
7nadin3 [17]

Answer:

Grand Tourer  Injection

7 0
3 years ago
What are the units of molality? A. mol/kg B. g/mol C. mol/L D. kg/mol
Serhud [2]

Answer:  A.mol/kg

The SI (international system) unit for molality is mol / kg, or solute moles per kg of peptides. A solution with a molality of 1 mol / kg is often described as "1 molal" or "1 m".

5 0
3 years ago
Read 2 more answers
Mix 200 g of copper at 100 °C with 1,000 g of water at 20 °C. Final temp. = 21.42°C a) How much heat energy (q) did the water ga
MrRissso [65]

Answer:

a) Q_w=5941.3J

b) C_{Cu}=0.378\frac{J}{g\°C}

Explanation:

Hello there!

In this case, when a hot substance is mixed with a cold one, we can evidence how the hot one is able to heat up the cold one as it cools down. Thus, the net heat flow for this problem can be set up as shown below:

Q_{Cu}+Q_{w}=0

Whereas the heats can be written in terms of mass, specific heat and temperatures:

m_{Cu}C_{Cu}(T_F-T_{Cu})+m_{w}C_{w}(T_F-T_{w})=0

Thus, we proceed as follows:

a. Here we compute Qw:

Q_w=1,000g*4.184\frac{J}{g\°C}(21.42\°C-20\°C) \\\\Q_w=5941.3J

b. Now, since this heat is equal to the negative of the heat contribution of copper (as it cools down), we can compute the specific heat of copper as shown down below:

C_{Cu}=\frac{-5941.3J}{200g(21.42\°C-100\°C)} \\\\C_{Cu}=0.378\frac{J}{g\°C}

Best regards!

7 0
3 years ago
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