Answer:
Q = 10.8 KJ
Explanation:
Given data:
Mass of Al= 100g
Initial temperature = 30°C
Final temperature = 150°C
Heat required = ?
Solution:
Specific heat of Al = 0.90 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30°C
ΔT = 120°C
Q = 100g×0.90 J/g.°C× 120°C
Q = 10800 J (10800j×1KJ/1000 j)
Q = 10.8 KJ
Carbon and iron alloys are called steel.
N2O4 is the only option from the list that represents a molecular compound, since compounds must contain at least two different atoms, although these can be from different groups.
Spring a has more potential energy then spring b
Answer:
Because water can absorb a lot of heat without significant changes in temperature, it can prevent change in the temperature, and therefore pressure, of the compressed air.To maintain a constant temperature, we again pass the compressed air through the same chambers, this time letting it take up heat from the water
