What do you set each term equal to in order to solve for all of the "roots" of a function? No links please :)
1 answer:
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vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= -
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Answer:
(i)x=-8
(ii)y>18
(iii)x>10
Step-by-step explanation:
I think the ans above is correct.
I hope it will help u....
