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White raven [17]
4 years ago
13

A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 320 with the surface of the l

awn. If a 249 N force is applied along the handle of the 21-kg mower, what is the normal force exerted by the lawn on the mower?
Physics
1 answer:
Virty [35]4 years ago
8 0

Answer:

N = 337.96 N

Explanation:

∅ = 32º

F = 249 N

m = 21 Kg

N = ?

We can apply:

∑ F = 0  (↑)

- Fy - W + N = 0   ⇒    N = Fy + W

⇒  F*Sin ∅ + m*g = N

⇒  N = (249 N*Sin32º) + (21 Kg*9.81 m/s²)

⇒  N = 337.96 N  (↑)

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A certain tuning fork vibrates at a frequency of 215 Hz while each tip of its two prongs has an amplitude of 0.832 mm. (a) What
Marysya12 [62]

Explanation:

It is given that,

Frequency of vibration, f = 215 Hz

Amplitude, A = 0.832 mm

(a) Let T is the period of this motion. It is given by the following relation as :

T=\dfrac{1}{f}

T=\dfrac{1}{215}

T=4.65\times 10^{-3}\ s

(b) Speed of sound in air, v = 343 m/s

It can be given by :

v=f\times \lambda

\lambda=\dfrac{v}{f}

\lambda=\dfrac{343\ m/s}{215\ Hz}

\lambda=1.59\ m

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5 0
4 years ago
Much of the energy of falling water in a waterfall is converted into heat. If all the mechanical energy is converted into heat t
Assoli18 [71]

Answer:

Explanation:

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P E = mgh = m x 9.8 x 111

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Let rise in temperature θ

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m x 4182 x θ =  1087.8 m

θ = 0.26 degree celsius .

6 0
3 years ago
A 0.56 kg block is suspended from the middle
Vadim26 [7]

Notice that both strings have the same length, so they form an isosceles triangle, which means the angles they make with the ceiling are congruent.

If this angle has measure θ, then the angle between the two strings T₁ and T₂ has measure 180° - 2θ. This is because the interior angles of any triangle sum to 180°.

By the law of cosines, we have

(1 m)² = (0.87 m)² + (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)

Solve for θ :

(1 m)² = 2 (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)

(1 m)² / (2 (0.87 m)²) = 1 - cos(180° - 2θ)

cos(180° - 2θ) = 1 - (1 m)² / (2 (0.87 m)²)

cos(180° - 2θ) ≈ 0.3394

180° - 2θ = arccos(0.3394)

180° - 2θ ≈ 70.159°

2θ ≈ 109.841°

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Answer:

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