Question

A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a radius that is 90 % of Earth’s (where Earth’s radius is approximately 6370 km ).The acceleration of the meteoroid due to the gravitational force exerted by the planet is most nearly

Answer 1

Answer:

The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/$s^{2}$

Explanation:

A meteoroid is in a circular orbit 600 km above the surface of a distant planet.

Mass of the planet = mass of earth = 5.972 x $10^{24}$ Kg

Radius of the earth = 90% of earth radius = 90% 6370 = 5733 km

The acceleration of the meteoroid due to the gravitational force exerted by the planet = ?

By formula, g = $\frac{GM}{r^{2} }$

where g is the acceleration due to the gravity

G is the universal gravitational constant = 6.67 x $10^{-11}$ $m^{3} kg^{-1} s^{-2}$

M is the mass of the planet

r is the radius of the planet

Substituting the values, we get

g =  $\frac{(6.67 * 10^{-11}) (5.972 * 10^{24}) }{5733^{2} }$

g = 12.12 m/$s^{2}$

The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/$s^{2}$