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alexandr1967 [171]
2 years ago
9

How many moles of oxygen are required to react with 12 moles of FeS2?

Chemistry
1 answer:
Radda [10]2 years ago
3 0
19 moles of O2 probably
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Provide the electronic structure diagram of propene showing all molecular orbitals​
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Answer:

Explanation:The pi-molecular orbitals in propene (CH3-CH=CH2) are essentially the ... This central carbon thus provides two p-orbitals – one for each pi bond – and these two different p-orbitals have to be perpendicular, leading to a twisted structure as shown: ... It all comes down to where the location of the electron-deficient carbon  

8 0
3 years ago
The number of particles in 1 mole of hydrogen gas is ________.
ivanzaharov [21]
Hidrogen gas is a diatomic gas, this is H2, which means that one molecule of gas has two atoms (every molecule of hydrogen gas consists in H2).

The particles in gases are the molecules, not atoms.

So, every molecule is a particle, and when you are told that you have 1 mole of hygrogen gas means that you have 1 mole of H2 molecules which is the same that 1 mole of particles.

Therefore, the answer is one mole.
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3 years ago
2SnO2 + 4H2
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2 years ago
Question 231.15 pts A 0.200 M solution of a weak monoprotic acid HA is found to have a pH of 3.00 at room temperature. What is t
MariettaO [177]

Answer:

The correct answer is: Ka= 5.0 x 10⁻⁶

Explanation:

The ionization of a weak monoprotic acid HA is given by the following equilibrium: HA ⇄ H⁺ + A⁻. At the beginning (t= 0) we have 0.200 M of HA. Then, a certain amount (x) is dissociated into H⁺ and A⁻, as is detailed in the following table:

               HA               ⇄        H⁺        +          A⁻

t= 0      0.200 M                     0                     0

t              -x                             x                       x

t= eq      0.200M -x               x                       x

At equilibrium, we have the following ionization constant expression (Ka):

Ka= \frac{ [H^{+}]  [A^{-} ]}{ [HA]}

Ka= \frac{x x}{0.200 M -x}

Ka= \frac{x^{2} }{0.200 M - x}

From the definition of pH, we know that:

pH= - log  [H⁺]

In this case, [H⁺]= x, so:

pH= -log x

3.0= -log x

⇒x = 10⁻³

We introduce the value of x (10⁻³) in the previous expression and then we can calculate the ionization constant Ka as follows:

Ka= \frac{(10^{-3})^{2}  }{0.200 - (10^{-3}) }= \frac{10^{-6} }{0.199}= 5.025 x 10⁻⁶= 5.0 x 10⁻⁶

5 0
3 years ago
Read 2 more answers
BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
lapo4ka [179]

Steps/Answers:

Jot down the metal name.

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Hope This Helps!       Have A Nice Day!!

5 0
3 years ago
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