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Artyom0805 [142]
2 years ago
9

Optical fibres are generally composed of silica, which has a refractive index of 1.44. How

Chemistry
2 answers:
NemiM [27]2 years ago
5 0

Answer:

from formula,

n = <u>speed</u><u> </u><u>of</u><u> </u><u>light</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

speed of light in medium

In Silica,

1.44 = (3e8m/s)/v

v= (3e8m/s)/1.44

v = 20.83e7m/s

v = 20.8 × 10^7m/s.

Light travels in silica at 20.8 × 10^7 m/s.

jasenka [17]2 years ago
4 0

Answer:

2.08 x 108 m/s

The speed of light in this fiber is found to be v = c/n = (3.00 x 108 m/s)/(1.44) = 2.08 x 108 m/s.

Explanation:

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Which of the following is a true statement?
LenKa [72]

Answer:

A

Explanation:

learned this in biology

8 0
2 years ago
1. Huntington’s disease is a dominant allele (not sex linked) that usually does not manifest itself until after age thirty- five
masya89 [10]

Answer:

a the mother is heterozygous so Aa

b would be aa

c. 50% as she could either get the dominant allele from her mother or not it is a coin flip

Explanation:for c the best way to do that one is to draw a punnitt square

4 0
2 years ago
What is the percent yield for a process in which 10.4g of CH3OH reacts and 10.1 g of CO2 is formed
monitta

Answer:

A. 70.7%

Explanation:

In the first step lets compute the molar mass of CH₃OH and CO

Molar Mass of CH₃OH =  1(12.01 g/mol) + 4(1.008 g/mol) +1(16.00 g/mol)

                                     = 32.042 g/mol

Molar Mass of CO₂      = 1(12.01 g/mol) + 2(16.00 g/mol)  

                                     = 44.01 g/mol

                                   

Mass of only one reactant i.e. CH₃OH is given so  it must be the limiting reactant. Next, the theoretical yield is calculated directly as follows:

Given mass of CH₃OH is 10.4 g. So we have:

                                     10.4g CH₃OH

Convert grams of CH₃OH to moles of CH₃OH utilizing molar mass of CH₃OH as:

                          1 mol CH₃OH / 32.042 g CH₃OH

Convert CH₃OH to moles of CO₂ using mole ratio as:

                             2 mol CO₂ / 2 mol CH₃OH

Convert moles of  CO₂ to grams of  CO₂ utilizing molar mass of  CO₂ as:

                           44.01 g/mol CO₂ / 1 mol CO₂

Now calculating theoretical yield using above steps:

[ 10.4 g CH₃OH ]  [1 mol CH₃OH / 32.042 g CH₃OH ]  [2 mol CO₂ / 2 mol CH₃OH]  [44.01 g/mol CO₂ / 1 mol CO₂]

Multiplication is performed here. We are left with 10.4 and 44.01 g CO₂ from numerator terms in the above equation and 32.042 from denominator terms after cancellation process of above terms. So this equation becomes:

= ( 10.4 ) ( 44.01 ) g CO₂ / 32.042

= 457.704/32/042

=  14.28 g CO₂

Theoretical yield =  14.28 g CO₂  

Finally compute the percent yield for a process in which 10.4g of CH₃OH reacts and 10.1 g of CO₂ is formed:

percent yield = (actual yield / theoretical yield) x 100

As we have calculated theoretical yield which is 14.28 g CO₂ and actual yield is 10.1 g CO₂ So,

percent yield = (10.1 g CO₂ / 14.28 g CO₂) x 100%

                       = 0.707 x 100%

                       = 70.7 %

Hence option A 70.7% yield is the correct answer.

8 0
3 years ago
Q15. Natural gas burns in air to form carbon dioxide and water to releasing heat. CHA(g) O2 (g) CO2 g) H20 (g) AH 802.3 kJ What
mestny [16]

Answer:

a) 0.115 g

Explanation:

The balanced reaction is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

To heat 55g of water, the energy in form of heat necessary can be calculated by:

Q = mcΔT

where Q is the heat, m is the mass, c is the specific heat (for water, c = 4.18 J/gºC), and ΔT is the variation of the temperature, which is 25ºC, so:

Q = 55x4.18x25

Q = 5747.5 J = 5.7475 kJ

So, for the reaction, 1 mol of CH₄ releases 802.3 kJ, so to release 5.7475 kJ will be necessary:

1 mol ---------------- 802.3 kJ

x ---------------- 5.7475 kJ

By a simple direct three rule:

802.3x = 5.7475

x = 7.164x10⁻³mol

The molar mass of CH₄ is : 12 (of C) + 4x1 (of H) = 16 g/mol

The mass is equal to the number of moles multiplied by molar mass, the:

m = 7.164x10⁻³x16

m = 0.115 g

6 0
3 years ago
Calculate the number of moles in 3.01 x 10²² atoms of calcium.​
Lera25 [3.4K]

Answer:

Using dimensional analysis:

3.01x1022 molecules CO2 x 1 mol CO2/6.02x1023 molecules x 44. g CO2/mole = 2.20 g CO2

Explanation:

8 0
2 years ago
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