Answer:
3.676 L.
Explanation:
We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
If n and P are constant, and have different values of V and T:
(V₁T₂) = (V₂T₁)
Knowing that:
V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,
V₂ = ??? L, T₂ = 40°C + 273 = 313 K,
Applying in the above equation
(V₁T₂) = (V₂T₁)
∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.
Answer:
The stronger electrolyte is the HCl
Explanation:
Stronger electrolyte are the ones, that in water, completely dissociates.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
HCl(aq) + H₂O(l) → H₃O⁺ (aq) + Cl⁻(aq)
Both are acids, they bring protons to medium but the hydrochloric completely dissociates.
HF (aq) + H₂O(l) ⇄ H₃O⁺(aq) + F⁻(aq) Ka
In the dissociation of weak electrolytes, they ionize but at the same time they bond again, so the reaction is always kept in equilibrium.
Answer:
rocky surface covered with landforms
Explanation:
Answer :
The correct answer is : 
Electron Affinity :
It is defined as energy released or absorbed when an electrons is added to neutral isolated atom in gaseous state .
The first electron affinity is the energy absorbed or released when one electron is to outermost shell of a neutral atom .
The first electron affinity is generally negative , when electron is added to non metals . While when electron is added to metals , the electron affinity is positive.
More the negative electron affinity , more the atom has tendency to accept the electron .
For example : F(g) + e⁻ → F⁻(g) ΔH⁰ = - 328.0
- 328.0 represents first electron affinity of Fluorine atom .
First electron affinity for Calcium can be written as :
The symbol for Calcium in its ground state is Ca . Since the electron (e⁻) is added so it is written on left side or reaction . The calcium will accept the electron and will form a negative ion as Ca⁻ .
Hence the equation goes as
AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)
Ksp=[A²⁺][B⁻]²
a=1.10 g/L
M=169 g/mol
c=a/M
[A²⁺]=c=a/M
[B⁻]=2c=2a/M
Ksp=(a/M)(2a/M)²=4(a/M)³
Ksp=4*(1.10/169)³=1.103×10⁻⁶
