I am struggling with this physics problem. Could someone please explain this problem to me in great detail? Thanks in advance!

Starting from rest, a disk rotates about its central axis with constant angular acceleration. In 5.00 s, it rotates 13.9 rad. Du

alisha [4.7K]

Answer:

(a) Angular acceleration is 1.112 rad/s².

(b) Average angular velocity is 2.78 rad/s .

Explanation:

The equation of motion in Rotational kinematics is:

θ = θ₀ + 0.5αt²

Here θ is angular displacement at time t, θ₀ is angular displacement at time t=0, t is time and α is constant angular acceleration.

(a) According to the problem, θ is 13.9 rad, θ₀ is zero as it is at rest and t is 5 s. Put these values in the above equation:

13.9 = 0 + 0.5α(5)²

α = 1.112 rad/s²

(b) The equation of average angular velocity is:

ω = Δθ/Δt

ω = $\frac{13.9}{5}$

ω = 2.78 rad/s

3 0

4 years ago

The period of a pendulum is the time it takes for the pendulum to make one full back-and-forth swing. The period of a pendulum

mixer [17]

Answer: 0.04 s

Explanation:

The given equation for the period $T$ of a pendulum when the acceleration due gravity is given in feet per squared second $g=32 ft/s^{2}$ is:

$T=2 \pi \sqrt{\frac{l}{32 ft/s^{2}}}$

Where $l=\frac{1}{18} ft$ is the length of the pendulum

$T=2 \pi \sqrt{\frac{\frac{1}{18} ft}{32 ft/s^{2}}}$

$T=0.04 s$

3 0

4 years ago

PLS HELP! WILL MARK BRANLIEST!!!

Finger [1]

Answer:

d. epicentral distance scale

Explanation:

The depth of focus from the epicenter, called as Focal Depth, is an important parameter in determining the damaging potential of an earthquake. Most of the damaging earthquakes have shallow focus with focal depths less than about 70km. Distance from epicenter to any point of interest is called epicentral distance

7 0

4 years ago

For general projectile motion, when the projectile is at the highest point of its trajectory, its acceleration is zero? A)The ho

Daniel [21]

Answer:

B) Its velocity is perpendicular to the acceleration.

Explanation:

For general projectile motion, the horizontal acceleration is 0 and the vertical acceleration is -g. This is true for all points on the trajectory.

At the highest point, the vertical velocity is 0. So you have only a horizontal velocity as well as a vertical acceleration. So the two are perpendicular.

4 0

4 years ago

While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.

lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0

3 years ago