X^2+8x+x+8 simplifies to x^2+9x+8
Answer:
A
Step-by-step explanation:
We are given a parabola with a vertex point of (2, 1) and a <em>y-</em>intercept of <em>y</em> = 4.
And we want to determine another point on the parabola.
Recall that a parabola is symmetric along the axis of symmetry, which is the <em>x-</em>coordinate of the vertex.
Note that since the <em>y-</em>intercept of the parabola is <em>y</em> = 4, this means that a point on our parabola is (0, 4).
To get from (2, 1) to (0, 4), we move two units left and three units up.
Since the parabola is symmetric along axis of symmetry, another point on the parabola will be two units right and three units up. This yields (2 + 2, 1 + 3) or (4, 4).
Our answer is A.
First, you need to get the denominators (the bottom number) the same. The smallest number to get them to is 15.
So, what you need to do is take 2/5 and multiply the bottom by 3 to get 15, and since you did it to the bottom, you need to do it to the top too. So you would get, 6/15.
Then, for 1/3, take the bottom number and multiply it by 5. Then, since you did it to the bottom, do it to the top as well. You would get 5/15.
Then, you need to put them side by side. You don't add the bottom, so your denominator would remain 15, but your numerator (top) would get added.
<u> 6</u> + <u>5</u> = <u>11</u>
15 15 15
Answer:
1/9 = 0.11111111 ( infinite )
Step-by-step explanation:
