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Anestetic [448]
3 years ago
12

Please i need it Lab: Calorimetry and Specific Heat

Chemistry
2 answers:
likoan [24]3 years ago
7 0

Answer:

step3:

aluminum- 11.98

copper-12.14

iron- 12.31

lead- 12.46

step5: 12.46, 52.31, 39.85

step7: 100, 22.4, 27.1, 4.7, 72.9

step5: 12.26, 52.49, 40.13

step7: 100, 22.7, 24.6, 1.9, 75.4

step5: 12.42, 52.66, 40.24

step7: 100, 22.5, 24.9, 2.4,75.1

step5: 12.34, 51.99, 39.65

step7: 100, 22.6, 23.3, 0.7, 76.7

step8: 0.90,0.35,0.44,0.12

Ulleksa [173]3 years ago
5 0

Answer:

its correct on edge

Explanation:

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gulaghasi [49]

Answer: In the possible source of error goes: Changing two variables at once to increase rate of data collection, Taking turns with lab partners performing different tasks in an experiment, Measuring millimeters with an ordinary meter stick

In the good experimental practice goes: Measuring in standard metric units, Doing repetitive trials of the same experiment, changing the angle of a ramp in an experiment by constant intervals

Explanation: hopefully this helps i got them right so it guaaranteed you will get this right aswell.

3 0
4 years ago
How many moles of LiOH are in a 4.5 M solution containing 1.5 L of water?
Anton [14]

Answer:

d

Explanation:

3 0
3 years ago
For the following reaction NaOH + Fe(NO3)3 - Fe(OH)3 + NaNO3 , what compound is the precipitate
likoan [24]
Compound Noah+Noah
7 0
3 years ago
Which of the following is true for the endothermic reaction Ba(OH)2(aq) + NH4NO3(aq) --> Ba(NO3)2(aq) + 2NH3(aq) + 2H2O(l)?
Alchen [17]
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6 0
3 years ago
2. If 1.204 X 1024 atoms of sodium is 20% of the total sodium atoms in sodium
GuDViN [60]

Answer:

584.2 g

Explanation:

Hello there!

In this case, since we know the 20% of the atoms correspond to sodium, we can compute the total atoms as shown below:

\frac{1.204 x10^{24}}{0.2}=6.02x10^{24}atoms

Which are also equal to 1 mol and the Avogadro's number of sodium chloride with a molar mass of 58.44 g/mol; thus, the grams of salt turn out to be:

6.02x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{58.44g}{1mol}\\\\=584.2g

Best regards!

3 0
3 years ago
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