How many moles of LiOH are in a 4.5 M solution containing 1.5 L of water?
1 answer:
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0.012moldm⁻³
Explanation:
Given parameters:
Mass of AgNO₃ = 1000mg
Volume of water = 500mL
Unknown:
Molarity of solution = ?
Solution:
The molarity of a solution is the number of moles of a solute dissolved in volume of solvent.
Molarity =
Number of moles of AgNO₃ = ?
Number of moles =
Molar mass of AgNO₃ = 108 + 14 + 3(16) = 170g/mol
convert mass to g;
1000mg = 1g
Number of moles = = 0.00588moles
convert the given volume to dm³;
1000mL = 1dm³;
500mL = 0.5dm³
Now solve;
Molarity = = 0.012moldm⁻³
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Molarity brainly.com/question/9324116
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