(a) weight of the sphere = 3.95 N
(b) buoyant force = 2.51 N
(c) sphere's apparent weight = 1.44 N
<h3>Further explanation</h3>
The basic formula of pressure that needs to be recalled is:
Pressure = Force / Cross-sectional Area
or symbolized:
<em>P = Pressure (Pa)</em>
<em>F = Force (N)</em>
<em>A = Cross-sectional Area (m²)</em>
Let us now tackle the problem !
<u>Given:</u>
Radius Sphere = R = 1.65 cm = 0.0165 m
Density of Platinum = ρ_p = 2.14 × 10⁴ kg/m³
Density of Mercury = ρ_m = 1.36 × 10⁴ kg/m³
<u>Asked:</u>
(a) weight of the sphere = w = ?
(b) buoyant force = F = ?
(c) sphere's apparent weight = w' = ?
<u>Solution:</u>
<h3>Part (a):</h3>
<h3>Part (b):</h3>
<h3>Part (c):</h3>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Pressure