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RoseWind [281]
3 years ago
7

How do I find the answer for the shaded region

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0
First i would do 28 x 11 then i would do 18 x 5 then subtract the answer you got from 18 x 5 to the answer you got from 28 x 11 (so sorry my wording is bad)
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The sum of three numbers is 94. The first number is six less than the second. The third number is three times the second. What a
Vika [28.1K]

Answer:

14, 20, 60

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

3 0
3 years ago
Read 2 more answers
Solve.<br> x^2+9x+2=0<br> thanks!
shtirl [24]
Step one:
ALWAYS set equation equal to zero, which in this case has already been done for us.

Step two:
Figure out what formula you need to use in order to solve in this case I'd use the Quadratic formula.

a=1
b=9
c=2

Quadratic formula:
x =  \frac{ - b +  -  \sqrt{(b) ^{2}  - 4(a)(c)} }{2(a)}
Then you would plug in the information.
x = \frac{ - 9+  -  \sqrt{(9) {}^{2} - 4(1)(2) } }{2(1)}
The solve for what is underneath the square root ONLY.
x =  \frac{ - 9 +  -  \sqrt{73} }{2}
Since you cannot solve this any further, your final two answers are...
x =   \frac{ - 9 +  \sqrt{73} }{2}
x =   \frac{ - 9 -  \sqrt{73} }{2}






3 0
3 years ago
The prostate-specific antigen (PSA) test is a simple blood test to screen for prostate cancer. It has been used in men over 50 a
Ugo [173]

The question is incomplete. I am writing the complete question below:

The prostate-specific antigen (PSA) test is a simple blood test to screen for prostate cancer. It has been used in men over 50 as a routine part of a physical exam, with levels above 4 ng/mL indicating possible prostate cancer. The test result is not always correct, sometimes indicating prostate cancer when it is not present and often missing prostate cancer that is present. Suppose that these are the approximate conditional probabilities of a positive (above 4 ng/ml) and negative test result given cancer is present or absent.

                                    Positive Result                 Negative Result

Cancer Present                   0.21                                       0.79

Cancer Absent                    0.06                                      0.94

In a large study of prostate cancer screening, it was found that about 6.6% of the population has prostate cancer.

What is the probability that the test is positive for a randomly chosen person from this population? (Enter your answer to five decimal places.)

P(Positive test) =

Answer:

P(Positive Result) = 0.0699

Step-by-step explanation:

We are given that 6.6% of the population has prostate cancer. So,

P(Cancer Present) = 0.066

P(Cancer Absent) = 1 - 0.066 = 0.934

From the given conditional probability table, we have:

P(Positive Result | Cancer Present) = 0.21

P(Positive Result | Cancer Absent) = 0.06

We need to find the probability that the result is positive. It can be either that the result is positive and cancer is present or the result is positive and the cancer is absent. So,

P(Positive Result) = P(Positive Result∩Cancer Present) + P(Positive Result∩Cancer Absent)

                             = P(Positive Result | Cancer Present)*P(Cancer Present) + P(Positive Result | Cancer Absent)*P(Cancer Absent)

                             = (0.21)*(0.066) + (0.06)*(0.934)

                             = 0.01386 + 0.05604

P(Positive Result) = 0.0699

5 0
3 years ago
Help please. I don’t understand and my teacher didn’t bother to teach us any of this and my brain hurts!!!!
const2013 [10]

Answer:

  23.  42 m^2

  24.  144 ft^2

  25.  68 cm^2

Step-by-step explanation:

The teacher should not need to spend any time teaching this. The area of the total figure is the sum of the areas of its parts. You already know that. And, you already know how to compute the areas of triangles and rectangles.

__

You may recall that the area of a triangle is ...

  A = 1/2bh

and the area of a rectangle with the same base and height is ...

  A = bh

So, a triangle with base b and height h has the same area as a rectangle with the same base (b) and half the height (h/2). Recognizing this makes these problems really simple.

__

23. The base of the rectangle and triangle is 7 m. The height of the triangle is 4 m, so its area is equivalent to adding 4/2 = 2 m to the 4 m height of the rectangle. Then the total area is ...

  A = (7 m)(4 m +(1/2)(4 m)) = (7 m)(6 m) = 42 m^2

__

24. Since there are two identical triangles of height 5, their total area is equal to that of a rectangle of height 5.

  A = (12 ft)(7 ft +5 ft) = 144 ft^2

__

25. The 5 cm height of the triangle makes it have an area equivalent to a rectangle 5/2 cm high.

  A = (8 cm)(6 cm +5/2 cm) = 68 cm^2

Note: we have read the fuzzy numbers as 8 cm wide, 6 cm high for the rectangle, and 5 cm high for the triangle. If your figure is different, please use the appropriate numbers in the calculation.

8 0
3 years ago
Just one or four please help ..
eduard
For num 4 the answer to six is 22 the reason is this formula so write this down for n aswell
n(n+1)/2+1 the example could be as we know for 1 cut we always will have 2 slices so 1(1+1)/2+1 is 2 and for 6 cuts 6(6+1)/2+1 is 22 therefore the answer to 6 cuts is 22 and to n cuts is the formula n(n+1)/2+1
7 0
3 years ago
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