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3 years ago

How do I find the answer for the shaded region

Mathematics

1 answer:

vampirchik [111]3 years ago

7 0

First i would do 28 x 11 then i would do 18 x 5 then subtract the answer you got from 18 x 5 to the answer you got from 28 x 11 (so sorry my wording is bad)

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Which is a discrete random variable?

sveta [45]

The answer is z result of flipping. Two coins

3 0

2 years ago

Y = 2x + 3<br> y = -3x + 8

snow_lady [41]

Answer:

i did not get that

Step-by-step explanation:

8 0

3 years ago

Solve the quadratic inequalities, by either graphing, or pure algebraic method:

BlackZzzverrR [31]

Answer:

less than/equal to -2

Or, greater than/equal to 2.5

Step-by-step explanation:

2x² - x - 10 ≥ 0

2x² - 5x + 4x - 10 ≥ 0

x(2x - 5) + 2(2x - 5) ≥ 0

(x + 2)(2x - 5) ≥ 0

Roots: -2, 5/2

x《 -2 or x》5/2

6 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago

The perimeter of a rectangle is 46 in and the diagonal is 17 in. Find the area of the rectangle.

OlgaM077 [116]

P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529

D= V L^2+l^2= 17
L^2+l^2=289

so 289+2l*L=529
2l*L=529-289=240
l*L=240:2
A=120

5 0

3 years ago