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levacccp [35]
2 years ago
14

or the formula C6H14 , calculate the index of hydrogen deficiency (IHD) and select all the types of unsaturation that might be p

resent in the molecule based on the IHD. The IHD is Which types of unsaturation might be present
Chemistry
1 answer:
Marizza181 [45]2 years ago
6 0

Answer:

See explanation

Explanation:

The term IHD means index of hydrogen deficiency. It tells us the number of missing hydrogen atoms from a given chemical formula. This number of missing hydrogen atoms corresponds to the number and type of multiple bonds in a given compound.

The formula for IHD is; IHD = C + 1 + N/2 – H/2 – X/2

C = Number of carbon atoms

N = Number of nitrogen atoms

H = Number of hydrogen atoms

X = Number of halogen atoms

Since;

N=0, X=0

Then;

IHD = C + 1 – H/2

Hence;

IHD = 6 + 1 - 14/2

IHD = 7 -7

IHD = 0

An IHD of 0 implies that there is no hydrogen deficiency or multiple bond in the molecule. It is purely a saturated compound.

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Perform the following operationand express the answer inscientific notation.7.00x10^5 - 5.00x10^4
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Taking into account the scientific notation,  the result of the subtraction is 6.5×10⁵.

<h3>Scientific notation</h3>

First, remember that scientific notation is a quick way to represent a number using powers of base ten.

The numbers are written as a product:

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<h3 /><h3>Subtraction in scientific notation</h3>

You want to subtract two numbers in scientific notation. It should be noted that when the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is 5.

Then all the values ​​are expressed as a function of the base 10 exponent with the highest exponent. In this case: 5.00×10⁴=0.500×10⁵

Taking the quantities to the same exponent, all you have to do is subtract what was previously called the number "a". In this case:

7.00×10⁵ - 0.500×10⁵= (7.00- 0.500)×10⁵= 6.5×10⁵

Finally, the result of the subtraction is 6.5×10⁵.

Learn more about scientific notation:

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