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levacccp [35]
2 years ago
14

or the formula C6H14 , calculate the index of hydrogen deficiency (IHD) and select all the types of unsaturation that might be p

resent in the molecule based on the IHD. The IHD is Which types of unsaturation might be present
Chemistry
1 answer:
Marizza181 [45]2 years ago
6 0

Answer:

See explanation

Explanation:

The term IHD means index of hydrogen deficiency. It tells us the number of missing hydrogen atoms from a given chemical formula. This number of missing hydrogen atoms corresponds to the number and type of multiple bonds in a given compound.

The formula for IHD is; IHD = C + 1 + N/2 – H/2 – X/2

C = Number of carbon atoms

N = Number of nitrogen atoms

H = Number of hydrogen atoms

X = Number of halogen atoms

Since;

N=0, X=0

Then;

IHD = C + 1 – H/2

Hence;

IHD = 6 + 1 - 14/2

IHD = 7 -7

IHD = 0

An IHD of 0 implies that there is no hydrogen deficiency or multiple bond in the molecule. It is purely a saturated compound.

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The half-life for beta decay of strontium-90 is 28.8 years. a milk sample is found to contain 10.3 ppm strontium-90. how many ye
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it is a process in which a nucleus of unstable atom emit energy in form of radiations like alpha particle , beta particle etc .

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The first order equation for radioactive decay can be expressed as :

ln \frac{N}{N_0}  = - k*t ----------- equation (1)

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1) To find deacy constant :

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T _\frac{1}{2} = \frac{ln2}{k} ---------equation (2)

Given : Half life of Strontium -90 = 28.8 years

Plugging value of T_\frac{1}{2} in above formula (equation 2) :

28.8 yrs = \frac{ln 2}{ k }

Multiply both side by k

28.8 yrs * k = \frac{ln 2 }{k} * k

Dividing both side by 28.8 yrs

\frac{28.8 yrs * k}{28.8 yrs} = \frac{ln 2}{28.8 yrs}

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k = 0.0241 yrs⁻¹

Step 2 : To find time :

Given : N₀ = 10.3 ppm N = 1.0 ppm k = 0.0241 yrs⁻¹

Plugging these value in equation (1) as :

ln (\frac{1.0 ppm}{10.3 ppm} ) = - 0.0241 yrs^-^1 * t

ln (0.0971 ) = -0.0241 yrs ^-^1 * t

(ln 0.0971 = - 2.33 )

Dividing both side by - 0.0241 yrs⁻¹

\frac{-2.33}{-0.0241 yrs^-^1} = \frac{-0.0241 yrs^-^1 * t}{-0.0241 yrs^-^1}

t = 96.68 yrs

Hence the concentration of Strontium-90 will drop from 10.3 ppm to 1.0 ppm is 96.68 yrs

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