Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Step-by-step explanation:
hope it is helpful to you
Answer:
Your power function is y=-2
Step-by-step explanation:
The way I found it was.
0=0, so, the function multiply by zero, and have no other term to add
A number (one in a case) gives as a result: -2. So, one, elevated to ANY power results in one, every time. So, I have 1, as a factor and -2 as a result. One is as well a factor that delivers a result equal to the other factor. (3)(1)=3 , (8987)(1)=8987. So, the other factor must be -2
Then I checked all the table, and the results were consistent.