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melisa1 [442]
2 years ago
14

The mass of an unidentified rock is 15.5 grams. Students determine the volume of the rock by placing the rock in a cylinder with

water. The students calculate the density of the rock. They determine the identity of the rock based on the density ranges in the table.
Rock Density Ranges
Rock Density Range
(g/cm3)
Coal 1.1-1.4
Dolomite 2.8-2.9
Peridotite 3.1-3.4
Sandstone 2.2-2.7

The students most likely have which type of rock?

A: Coal
B: Dolomite
C: Sandstone
D: Peridotite
Chemistry
1 answer:
Otrada [13]2 years ago
6 0
Answer: I’m pretty sure that it’s C.
Hope this helps :)
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Calculate the density for a rectangular block using the following measurements: Length = 10 cm, Width = 1.1 cm, Height = 15 cm,
Ksivusya [100]

Answer:

0.40 g/cm3

Explanation:

density = mass / volume.

mass = 65.2 grams

volume = 10*1.1*15=165 cm3

so density = 65.2/165=0.40 g/cm3

3 0
2 years ago
What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme
boyakko [2]

<u>Answer:</u> The longest wavelength of light is 656.5 nm

<u>Explanation:</u>

For the longest wavelength, the transition should be from n to n+1, where: n = lower energy level

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.096776\times 10^7m^{-1}

n_f = Higher energy level = n_i+1=(2+1)=3

n_i= Lower energy level = 2    (Balmer series)

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m

Converting this into nanometers, we use the conversion factor:

1m=10^9nm

So, 6.565\times 10^{-7}m\times (\frac{10^9nm}{1m})=656.5nm

Hence, the longest wavelength of light is 656.5 nm

4 0
3 years ago
You have 16.7 grams of hydrogen and 15.4 grams of oxygen in a synthesis rxn. Which is the limiting reagent?
sleet_krkn [62]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of hydrogen = 16.7 g

Mass of oxygen = 15.4 g

Limiting reactant = ?

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 16.7 g/ 2 g/mol

Number of moles = 8.35 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 15.4 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of both reactant with product,

                 

                             H₂           :          H₂O

                              2            :            2

                             8.35        :            8.35

                             O₂           :          H₂O

                               1            :            2

                             0.48        :        2×0.48 = 0.96 mol

The number of moles of water produced by oxygen are less so it will limiting reactant.

3 0
3 years ago
What is the balanced form of the chemical equation shown below?
mihalych1998 [28]

The balanced form of the chemical equation shown is N₂(g) + 3H₂(g) → 2NH3(g) (option A).

<h3>What is a balanced equation?</h3>

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation is the same.

According to this question, the chemical equation between nitrogen and hydrogen is given as follows: N₂(g) + H₂(g) → NH3(g)

The balanced form of the chemical equation shown is N₂(g) + 3H₂(g) → 2NH3(g).

Learn more about balanced equation at: brainly.com/question/7181548

#SPJ1

5 0
2 years ago
Hard water often contains dissolved Ca2+ and Mg2+ ions. One way to soften water is to add phosphates. The phosphate ion forms in
katrin2010 [14]

Answer:

22.4269 grams of sodium phosphate must be added to 1.4 L of this solution to completely eliminate the hard water ions

Explanation:

We will first write the balanced equation for this scenario

3 CaCl2 + 2 Na3PO4 ----> 6 NaCl + Ca3 (PO4)2

3 Mg(NO3)2 + 2 Na3PO4 -----> 6 NaNO3 + Mg3 (PO4)2

The ratio here for both calcium chloride and magnesium nitrate is 3:2

The number of moles of each compound is equal to

0.054 * 1.4 = 0.0756\\0.093* 1.4 = 0.1302

Using the mole ratio of 3:2, convert each to moles of sodium phosphate.

0.0756 mole of CaCl2 is equal to 0.05\\ Na3PO4

0.1302 mole of CaCl2 is equal to 0.0868 Na3PO4

Converting moles of sodium phosphate to grams of sodium phosphate we get

(0.05 +0.0868) * 163.94 g/mol

22.4269 grams of sodium phosphate must be added to 1.4 L of this solution to completely eliminate the hard water ions

8 0
3 years ago
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