P(A) = 0.7 P(A and B) = 0.21 P(B\A) =

Mathematics

1 answer:

umka2103 [35]4 years ago

4 0

Answer:

1) Conditional probability $P(B/A)=0.3$

2) $P(A and B)=0.28$

Step-by-step explanation:

1) Given that P(A)=0.7 and P(A and B)=0.21

To find the conditional probability :

Conditional probability $P(B/A)=\frac{P(A and B}{P(A)}$ when P(A)>0

Substitute the values P(A)=0.7 and P(A and B)=0.21 in above formula we get

$P(B/A)=\frac{0.21}{0.7}[tex]=0.3$

Therefore $P(B/A)=0.3$

Therefore the Conditional probability $P(B/A)=0.3$

2) Given that P(A)=0.4 and P(B)=0.7 and also given that Events A and B are independents

To find P(A and B) :

$P(A and B)=P(A)\times P(B)$

Substitute the values P(A)=0.4 and P(B)=0.7 in above formula we get

$P(A and B)=(0.4)\times (0.7)$

=0.28[/tex]

Therefore $P(A and B)=0.28$

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