Answer: 22368.4 Liters
Explanation:
Initial Volume of gas V1 = 20000 liters
Initial pressure of gas P1 = 850 torr
Final volume V2 = ?
Final (standard) pressure P2 = 760 torr
Apply the formula for Boyle's law:
P1V1 = P2V2
850torr x 20000L = 760torr x V2
V2 = (850torr x 20000L)/ 760torr
V2 = (17000000)/760torr
V2 = 22368.4L
Thus, the volume of the gas at standard pressure is 22368.4 Liters
The object and description that matches is Object 2 and T.
Object 1 has no matching description.
<h3>Fish Aquarium Filter </h3>
A Fish aquarium filter is a filter whose function is to clean the water of debris, removes the toxic buildup of ammonia and nitrates, and aerates the water so that fish can in a conducive environment and breathe properly
<h3>Engine Oil Filter</h3>
An engine oil filter is a filter whose function is to filter and remove contaminants that may be present in the engine oil, transmission oil, lubricating oil, or hydraulic oil in order for proper functioning of the engine.
Therefore, the object and description that matches is Object 2 and T.
Object 1 has no matching description.
Learn more about filters and their uses at: brainly.com/question/10719424
Non-polar covalent
Explanation:
Propane is made up of non-polar covalent bonds and it can be expected to dissolve in hexane and to not dissolve in water.
Propane is an hydrocarbon gas.
It forms by sharing of electrons between two atoms with very low electronegativity differences.
This differences results in equal sharing of the shared electron. Therefore they form a non-polar covalent bond.
Water is a polar covalent compound and cannot dissolve compounds that are not polar like propane.
Propane will only dissolve in a like substance like hexane which is equally non-polar.
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Covalent compounds brainly.com/question/3109255
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Answer:
3.8 M
Explanation:
Volume of acid used VA= 57.0 - 37.5 = 19.5 ml
Volume of base used VB= 67.8 - 45.0 = 22.8 ml
Equation of the reaction
2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)
Number of moles of acid NA= 2
Number of moles of base NB= 1
Concentration of acid CA= ???
Concentration of base CB= 1.63 M
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CA= CBVBNA/VANB
CA= 1.63 × 22.8 × 2/ 19.5 × 1
CA= 3.8 M
HENCE THE MOLARITY OF THE ACID IS 3.8 M.
