Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer:
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Step-by-step explanation:
Answer: 500,000
Step-by-step explanation:
3.5M/7=500,000
For quite some time now, calculators have had statistical functions built in. Here we need to use the stat. function normalcdf, which has only two inputs when we're working with z scores instead of raw scores.
Here,
normalcdf(-100,1.25) = 0.894
This same result could be obtained using a table of z-scores.
Answer:
14,146 years
Step-by-step explanation:
The annual multiplier is (1 -0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.
0.5 = 0.999951^t
log(0.5) = t·log(0.999951)
log(0.5)/log(0.999951) = t ≈ 14,145.514
The half-life is about 14,146 years.
