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Elza [17]
3 years ago
9

Х Solve for x. 43° 22

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0
11.3 did that help you
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Write an equation of a line through (5,6) and (-1,4)
Dvinal [7]
First, you would do y1-y2, which would be 6-4, which would be 2. Then you would do x1-x2, which would be 5-(-1), which equals 6. Then you would do 2/6, which equals 1/3. Then you would do (1/3)×-1, which would be -1/3. Then, 4-(-1/3), which would be 4 1/3. The equation is y=(1/3)x+4 1/3
7 0
3 years ago
Read 2 more answers
How do I work this math problem?<br> (9 x 10 to the sixth power) (8 x 10 negative 4 power?
Kamila [148]
90^6=531441000000

80^-4= 1/80^4= 1/4960000
For this, use negative power rule x^-a= 1/x^a
7 0
3 years ago
The Wilson family had 5 children. Assuming that the probability of a child being a girl is 0.5, find the probability that the Wi
Dafna11 [192]

Answer:

0.813

0.500

Step-by-step explanation:

Use binomial probability.

P = nCr p^r q^(n−r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

In this problem, n = 5, p = 0.5, and q = 0.5.

"At least 2 girls" means r = 2, 3, 4, or 5.

Or, we can use the complement.

P(at least 2 girls) = 1 − P(at most 1 girl)

P(at least 2 girls) = 1 − P(r=0 or r=1)

P(at least 2 girls) = 1 − ₅C₁ (0.5)¹ (0.5)⁵⁻¹ − ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰

P(at least 2 girls) = 1 − 5 (0.5) (0.5)⁴ − 1 (1) (0.5)⁵

P(at least 2 girls) = 1 − 6 (0.5)⁵

P(at least 2 girls) ≈ 0.813

"At most 2 girls" means r = 0, 1, or 2.

P(at most 2 girls) = P(r=0, r=1, or r=2)

P(at most 2 girls) = ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰ + ₅C₁ (0.5)¹ (0.5)⁵⁻¹ + ₅C₂ (0.5)² (0.5)⁵⁻²

P(at most 2 girls) = 1 (1) (0.5)⁵ + 5 (0.5) (0.5)⁴ + 10 (0.5)² (0.5)³

P(at most 2 girls) = 16 (0.5)⁵

P(at most 2 girls) = 0.500

4 0
3 years ago
working together 9 friends pick up 23 2/5 bags of apples and an orchard they divide the bags of apples equally between them how
Citrus2011 [14]
Simply divide 23 and 2/5 bags of apples between 9 friends:

23 and 2/5 bags ÷ 9 friends= 117/5 bags ÷ 9 friends
                                              =  13/5 bags
                                              = 2 and 3/5 bags

Therefore, each friend receives 2 and 3/5 bags of apples.

Hope this helps!
5 0
3 years ago
Michael jogs at 3 miles per hour and Jack runs at 4.5 miles per hour. If Michael starts at 2:00 pm and Jack starts on the same c
tresset_1 [31]

Answer:

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

Step-by-step explanation:

Micheal  runs 3 miles in one hour or 60 minutes.

In one minute he runs 3/60= 1/20  or 0.05miles.

Jack runs 4.5 miles in one hour or 60 minutes.

In one minute he runs 4.5/60= 45/600= 9/120= 3/40  or 0.075 miles.

So Jack is 0.075/0.05 = 1.5 times faster than Micheal.

or Micheal is 1.5 times slower than Jack.

Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles

Micheal start at 2:00 pm and at 3 pm he will run 0.05(60 minutes)= 3 miles

So at 3 pm both will have covered equal distance= 3miles.

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

3 0
3 years ago
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