Answer:
16 cm
Explanation:
For protons:
Energy, E = 300 keV
radius of orbit, r1 = 16 cm
the relation for the energy and velocity is given by
So, 
.... (1)
Now,
Substitute the value of v from equation (1), we get
Let the radius of the alpha particle is r2.
For proton
So, 
... (2)
Where, m1 is the mass of proton, q1 is the charge of proton
For alpha particle
So, 
... (3)
Where, m2 is the mass of alpha particle, q2 is the charge of alpha particle
Divide equation (2) by equation (3), we get
q1 = q
q2 = 2q
m1 = m
m2 = 4m
By substituting the values
So, r2 = r1 = 16 cm
Thus, the radius of the alpha particle is 16 cm.
Answer:
4200 Joules
Explanation:
Work done =force x distance
From the question , we’re given f =350N ,
d = 12m
Using the above formula, we have
Workdone = 350 x 12
= 4200 Joules
Answer:
Lifting a bag of groceries
Answer:
The value is 
Explanation:
From the question we are told that
The magnitude of the horizontal force is 
The mass of the crate is 
The acceleration of the crate is 
Generally the net force acting on the crate is mathematically represented as
Here 
is force of kinetic friction (in N) acting on the crate
So
=>
M1 v1 = (m1 + m2)v2.
All of the exponents should be lowered to the bottom right of the letters.
