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7 months ago

hi, Need help with triangle law of vector addition worksheet and a verifying Newtons second law worksheet?

1 answer:

5 0

Use Newton's second law and the free body diagram to determine the net force and acceleration of an object. In this unit, the forces acting on the object were always directed in one dimension.

The object may have been subjected to both horizontal and vertical forces but there was no single force directed both horizontally and vertically. Moreover, when free-body diagram analysis was performed, the net force was either horizontal or vertical, never both horizontal and vertical.

Times have changed and we are ready for situations involving two-dimensional forces. In this unit, we explore the effects of forces acting at an angle to the horizontal. This makes the force act in two dimensions, horizontal and vertical. In such situations, as always in situations involving one-dimensional network forces, Newton's second law applies.

Learn more about Newton's second law here:-brainly.com/question/25545050

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The sum of all forces acting on an object

Zina [86]

Answer:

The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

Explanation:

put in your own words PLEASE, hope it helps

4 0

2 years ago

1 2 3 What would happen if Bulb 1 goes out?

aleksandrvk [35]

Answer:

it will explode

Explanation:

because it will explode

5 0

2 years ago

Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our sun but have a much smaller dia

Crank

Answer:

Wn = 9.14 x 10¹⁷ N

Explanation:

First we need to find our mass. For this purpose we use the following formula:

W = mg

m = W/g

where,

W = Weight = 675 N

g = Acceleration due to gravity on Surface of Earth = 9.8 m/s²

m = Mass = ?

Therefore,

m = (675 N)/(9.8 m/s²)

m = 68.88 kg

Now, we need to find the value of acceleration due to gravity on the surface of Neutron Star. For this purpose we use the following formula:

gn = (G)(Mn)/(Rn)²

where,

gn = acceleration due to gravity on surface of neutron star = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

Mn = Mass of Neutron Star = Mass of Sun = 1.99 x 10³⁰ kg

Rn = Radius of neutron Star = 20 km/2 = 10 km = 10000 m

Therefore,

gn = (6.67 x 10⁻¹¹ N.m²/kg²)(1.99 x 10³⁰ kg)/(10000)

gn = 13.27 x 10¹⁵ m/s²

Now, my weight on neutron star will be:

Wn = m(gn)

Wn = (68.88)(13.27 x 10¹⁵ m/s²)

Wn = 9.14 x 10¹⁷ N

3 0

3 years ago

Calculate the rate of heat generation in kW due to the burning of the fuel when you drive a car rated at 34 MPG (miles per gallo

alexira [117]

Answer:

Explanation:

Let us calculate gallon used in one hour .

It travels 70 miles in one hour

in 70 miles it uses 70 / 34 gallons of fuel

70 / 34 gallons = 70 / 34 x 3.7854 kg

= 7.8 kg

heat generated = 7.8 x 44 x 10⁶ J

= 343.2 x 10⁶ J

This is heat generated in one hour

heat generated in one second = 343.2 x 10⁶ / 60 x 60 J/s

= 95.33 x 10³ J /s

= 95.33 kW.

4 0

3 years ago

A student holds one end of a thread, which is wrapped around a cylindrical spool, as shown above. The student then drops the spo

lesya [120]

by energy conservation we know that

KE or rotation + KE of translation = gravitational PE

now we have

$\frac{1}{2}I\omega^2 + \frac{1}{2}mv^2 = mgH$

also we know that

$v = R\omega$

now we have

$\frac{1}{2}(\frac{1}{2}mR^2)\omega^2 + \frac{1}{2}m(R\omega)^2 = mgH$

$\frac{3}{4}mR^2\omega^2 = mgH$

$\omega = \sqrt{\frac{4gH}{3}}/R$

now when it is rolling on ground the torque acting on it due to friction force is given by

$\tau = R F_f$

$\tau = \mu mg R$

$\alpha = \frac{\mu mg R}{\frac{1}{2}mR^2}$

$\alpha = \frac{2 \mu g}{R}$

now angular speed at any time is given as

$\omega = \omega_i + \alpha t$

$\omega = \sqrt{\frac{4gH}{3}}/R -\frac{2 \mu g}{R} t$

so above is the angular speed in terms of time "t"

7 0

3 years ago