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valentinak56 [21]
2 years ago
12

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is

believed that the machine is underfilling the bags. A 26 bag sample had a mean of 413 grams with a standard deviation of 24. Assume the population is normally distributed. A level of significance of 0.02 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Mathematics
1 answer:
Anastaziya [24]2 years ago
3 0

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, \overline x = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}

We get;

t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t =  2.166587

The p-value is obtained using an online source as p(t ≤  -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

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Anna35 [415]
ANSWER

1: 1/2

2: 4/9

3: 8

4: 5/18

5: Theo= What should happen

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4 0
1 year ago
A computer can be classified as either cutting dash edge or ancient. Suppose that 86​% of computers are classified as ancient. ​
Leno4ka [110]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86​% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

P(ancient)=0.86

(a) To find the probability that two computers are chosen at random and both are ancient​ you must,

The probability that the first computer is ancient is P(ancient)=0.86 and the probability that the second computer is ancient is P(ancient)=0.86

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396

(b) To find the probability that seven computers are chosen at random and all are ancient​ you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge​ you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

P(C)=1-P(A)=1-0.3479=0.6520

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

5 0
2 years ago
Lydia wanted to flip a coin and roll a die at the same time, but she also wondered what the probability of the coin landing on h
exis [7]

Answer:

incorrect

Step-by-step explanation:

this is because it would be 1/2 and 1/6. you would have to multiply the bases for a probability of 1/12

7 0
3 years ago
SIR MELIODAS <br><br><br> CAPTION <br><br><br> MEL|ODAS
dalvyx [7]

Answer:

great

Step-by-step explanation:

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My name is Ann [436]

Answer:10.25

Step-by-step explanation:

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