5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.

where,
- <em>c: specific heat capacity of gold</em> (0.129 J/g.°C)
- ΔT: change in the temperature

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
You can learn more about heating here: brainly.com/question/1105305
<u>Answer:</u> The final temperature of the coffee is 43.9°C
<u>Explanation:</u>
To calculate the final temperature, we use the equation:

where,
q = heat released = 
m = mass of water = 10.0 grams
C = specific heat capacity of water = 4.184 J/g°C
= final temperature = ?
= initial temperature = 20°C
Putting values in above equation, we get:

Hence, the final temperature of the coffee is 43.9°C
<u>Given:</u>
Time taken by the electromagnetic radiation, t = 33 fs
<u>To determine:</u>
The distance (d) travelled
<u>Explanation:</u>
Time taken = 33 fs (femtosecond)
1 fs = 10⁻¹⁵ s
Thus t = 33 *10⁻¹⁵ s
Speed of electromagnetic radiation = 3*10⁸ m/s
Distance = Speed * Time = 3*10⁸ ms-1 * 33*10⁻¹⁵ s = 99*10⁻⁷ m
Ans: distance traveled = 9.9*10⁻⁶ m
(I think) you would have to divided the number i dont know the exact answer but ya hope this help