The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.
<h3>How do we calculate grams from moles?</h3>
Grams (W) of any substance will be calculated by using their moles (n) through the following equation:
M = molar mass
And moles of the gas will be calculated by using the ideal gas equation as:
P = pressure = 1atm
V = volume = 40L
n = moles = ?
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 200K
On putting these values on the above equation, we get
n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles
- Now grams of hydrogen gas will be calculated by using the first equation as:
W = (2.44mol)(2g/mol) = 4.88g
Hence required mass of hydrogen gas is 4.88g.
To know more about ideal gas equation, visit the below link:
brainly.com/question/15046679
#SPJ1
Answer:
I- It says horizon so.....what....wth ._.
Explanation:
5.20 mol C6H12* (84.2 g/mol C6H12)= 4.38*10^(2) g C6H12.
The answer should only have three significant figures, according to the numbers in the problem.
Hope this is helpful~
Secondary air pollutants are the ones that are formed as a result of reactions
between primary pollutants and other elements in the atmosphere, such as ozone
