Question

What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L

Answer 1

Answer:

The pressure is 1, 22 atm.

Explanation:

We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).

0°C=273 K   25°C= 273 + 25= 298 K

PV=nRT   -----> P= (nRT)/V

P= (0,5 mol x 0,082 l atm /K mol x 298 K)/ 10 L

P= 1, 2218 atm