1) First of all, let's find the resistance of the wire by using Ohm's law:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
by using the following relationship:
Where A is the cross-sectional area of the wire and L its length.
We already have its length
, while we need to calculate the area A starting from the radius:
And now we can find the resistivity:
Answer:
Parameter is population mean = 65 c
Explanation:
There are two important aspects in the study of samples and inferring the behaviour of population.
TO know the mean of the population, normally we draw different samples and find their mean. The mean of all means will be an estimate for the populatio mean. By central limit theorem, mean of a sample tends to be normal as sample sizes grow with estimated mean as mean of sample.
While a statistic describes a sample, a parameter describes an entire population.
Here 65 degrees C is for entire population hence this is a parameter.
Answer:
<em>The mass of the apple is 0.172 kg (172 g)</em>
Explanation:
<u>The Law Of Conservation Of Linear Momentum
</u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of both momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
If both masses stick together after the collision at a common speed v', then:
We are given the mass of an arrow m1=43 g = 0.043 kg traveling at v1=84 m/s to the right (positive direction). It strikes an apple of unknown mass m2 originally at rest (v2=0). The common speed after they collide is v'=16.8 m/s.
We need to solve the last equation for m2:
Factoring m2 and m1:
Solving:
Substituting:
The mass of the apple is 0.172 kg (172 g)
<span>1. The potential energy is 34.3J
2. The kinetic energy is 61,875J.
3. A 0.5 kg ball is at the top of a 20 meter tall hill.
a) What is the ball's kinetic energy ? The ball's kinetic energy is zero.
b) what is the ball's potential energy ? The ball's potential energy is 98.1J.
c) what is the ball's mechanical energy ? The ball's mechanical energy is 98.1J.
4. 2.0 kg toy has been thrown in the air it is 1.5m above the ground and is moving up at 3.0 m/s
a) What is the toy's kinetic energy ? The toy's kinetic energy is 9J.
b) what is the toy's potential energy ? The toy's potential energy is 29.43J.
c) what is the toy's mechanical energy ? The toy's mechanical energy s 38.43J.</span>
Answer:
4.05 m/s
Explanation:
We shall represent the different velocity in vector form
Newton runs due north at 3.90 m/s, with respect to standing Daniel .
V_n = 3.9 j
Let Pauli runs with respect to standing Daniel with velocity X .
Then relative velocity of Newton with respect to running Pauli will be
3.9 j - X
Give that
relative velocity of Newton with respect to running Pauli = 1.1 i ( 1.1 due east )
So
3.9 j - X = 1.1 i
X = -1.1 i + 3.9 j .
Magnitude of X
X² = 1.1 ² + 3.9²
X = 4.05 m/s
So Pauli runs with respect to standing Daniel with velocity 4.05 m /s .
Direction will be , west of north at angle θ ,
Tan θ = 1.1 / 3.9