1.00 x 10^8 kg of clear liquid (specific heat

A 25.0-g sample of copper at 363 K is placed in I 00.0 g of water at 293 K. The copper and water quickly come to the sa me tempe

Simora [160]

Answer:

Final temperature is 295K

Explanation:

Where the sample of copper is placed in the water, the heat transferred from the copper is equal that the heat absorbed by the water.

The heat transferred from the copper is:

C× $\frac{1mol}{63,546g}$ ×mass×ΔT

Where C is molar heat capacity of copper (24,5J/molK)

Mass is 25,0g

And ΔT is final temperature - initial temperature (X-363K)

Also, the heat absorbed by the water is:

-C× $\frac{1mol}{18,02g}$ ×mass×ΔT

Where C is molar heat capacity of water (75,2J/molK)

Mass is 100,0g

And ΔT is final temperature - initial temperature (X-293K)

As heat transferred is equal to heat absorbed:

24,5J/molK× $\frac{1mol}{63,546g}$ ×25,0g×(X-363K) = -75,2J/molK× $\frac{1mol}{18,02g}$ ×100,0g× (X-293K)

9,64X J/K - 3499J = - 417X J/K + 122273J

426,64X J/K = 125772 J

X = 295K

Final temperature is 295K

I hope it helps!

6 0

4 years ago

In a tug of war, when one team is pulling with a force of 85 N and the other 40 N, what is the net

olya-2409 [2.1K]

85 N - 40 N = 45 N
And depending on direction the greater force is being pulled towards

4 0

3 years ago

A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in t

Vladimir [108]

Answer:

The index of refraction of the glass is 1.3

Explanation:

Given data:

i = incident angle = 50°

r = refracted angle = 36.1°

The index of refraction according Snell´s law is:

$n=\frac{1*sini}{sinr} =\frac{1*sin50}{sin36.1} =1.3$

4 0

4 years ago

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that

Natasha2012 [34]

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

$T = \frac{t}{n}$

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

$T = \frac{135\ s}{98}$

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

$T = 2\pi \sqrt{\frac{l}{g}}$

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

$(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}$

g = 11.2 m/s²

3 0

3 years ago

What is an element that needs to lose or gain 4 valence electrons in order to become stable?

tiny-mole [99]

Answer:

Elements in Group 14 could lose four, or gain four electrons to achieve a noble gas structure. In fact, if they are going to form ions, Group 14 elements form positive ions. Carbon and silicon form covalent bonds. Carbon's millions of organic compounds are all based on shared electrons in covalent bonds.

Explanation:

4 0

3 years ago