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irina [24]
3 years ago
13

naturally occurring bromine molecules, br2 have masses of 158, 160, and 162. they occur in the relative abundances 25.69%, 49.99

%, and 24.31% respectively. what is the average atomic mass of bromine atoms? what is the relative abundance of 79br and 81br isotopes?
Chemistry
1 answer:
4vir4ik [10]3 years ago
4 0
The average atomic mass of an element can be determined by multiplying the individual masses of the isotopes with their respective relative abundances, and adding them. 

Average atomic mass of Br = 158 amu(0.2569) + 160 amu(0.4999) + 162 amu(0.2431)
Average atomic mass = 159.96 amu

As described in the problem, the relative abundance for Br-79 is 25.69%. This is because 2 atoms of Br is equal to 79*2 = 158 amu. Similarly, the relative abundance of Br-81 is 81*2 = 162, which is 24.31%.
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A 0.04328 g sample of gas occupies 10.0-mL at 294.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C
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<u>The molecular formula of the gas sample = C_2Cl_2 </u>

<u>Lewis structure is shown in the image below.</u>

<u>The geometry around each carbon atom is linear.</u>

Explanation:

Given that:

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Using ideal gas equation as:

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moles = \frac{Mass\ taken}{Molar\ mass}

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% moles of C = 25.305 / 12.0107 = 2.1069

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Molar mass of Cl = 35.453 g/mol

% moles of Cl = 74.695 / 35.453 = 2.1069

Taking the simplest ratio for C and Cl as:

2.1069 : 2.1069  = 1 : 1

<u>The empirical formula is = CCl</u>

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 35.5 = 47.5 g/mol

Molar mass = 94.9747 g/mol

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Molecular mass = n × Empirical mass

94.9747 = n × 47.5

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<u>The molecular formula of the gas sample = C_2Cl_2 </u>

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The total number of the valence electrons  = 4*2 + 7*2 = 22

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<u>So, it is of linear shape.</u>

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