Uranium-232 will remain 11.72 g
<h3>Further explanation
</h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:

T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t 1/2 = half-life = 68.8 years
T = duration of decay = 344 years
No= initial sample = 375 g
Uranium-232 remain :

Answer:
2S + 3O 2 --->2SO 3 synthesis
Explanation:
2Na + 2H 2O -->2NaOH + H 2 single replacement
2S + 3O 2 --->2SO 3 synthesis
2H 2O 2 --->2H 2O + O 2 decomposition
CaCl 2 + F 2 ---> CaF 2 + Cl 2 single replacement
Answer:
Explanation:
Remark
You have 2 facts that you got from the experiment. The first is that the mass of the wood is 63.85 grams and the volume can be calculated.
From there, the desity can be found.
Givens
m = 63.85 grams
vo = 50 mL
vf = 125 mL
Solution
Volume = vf - vo
Volume = 125 mL - 50 ml. This gives you the amount of water that has been moved aside (called displaced)
volume = 75 mL
D = 63.85 grams/ 75 mL
D = 0.851 grams / mL
Some woods actually do have a density less than 1 which is the density of water. These woods float.
Answer:
It is necessary because Trans-cinnamic is a limiting reagent in the mixture reaction while Bromine is the excess reagent
Explanation:
It is necessary to maintain excess bromine in the reaction mixture because Bromine is the excess reagent in the reaction mixture and if it's quantity is less it would consume the limiting reagent ( Trans-cinnamic ) completely . hence Bromine should maintain excess quantity in the reaction mixture