Answer:
The young tree, originally bent, has been brought into the vertical position by adjusting the three guy-wire tensions to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Determine the force and moment reactions at the trunk base point O. Neglect the weight of the tree.
C and D are 3.1' from the y axis B and C are 5.4' away from the x axis and A has a height of 5.2'
Explanation:
See attached picture.
Answer:
The acceleration produced is
Explanation:
By the second law of Newton, the force F is equal to:
F = ma
Where m is the mass of the object and a is the acceleration produced. So if The force gives the standard 1 kg mass an acceleration of 1.00 m/s2, that means that the force apply on A and B is equal to:
F = (1Kg) * (1.00m/s2) = 1 N
Then, if this force on A produce an acceleration of 0.530 , the mass of A is:
At the same way, if this force on B produce an acceleration of 0.344 , the mass of B is:
Therefore, if they are attached and the same force is applied, the acceleration is:
The density of an object is the ratio of its mass over the volume. This translates to the amount of substance present in a certain space and can mathematically be expressed as,
density = mass / volume
In this item, we are given that the object of mass 1.41 kg is able to displace 0.314 L of liquid. The volume of water displaced is also the volume of the object. Hence,
density = 1.41 kg / 0.314 L = 4.49 kg/L
Then, we convert the calculated volume of g/mL.
density = (4.49 kg/L)(1 L / 1000 mL)(1000 g/1 kg)
<em> density = 4.49 g/mL</em>
Answer:
Refractive index = 1.15
Explanation:
As we know for constructive interference of reflected light the path difference of two reflected light rays must be integral multiple of the wavelength
so here we have
now here we know that
now we have
This one is a piece 'o cake if you know the formula for
Kinetic Energy, and impossible if you don't.
It is: KE = (1/2) (mass) (speed²) .
For this object: KE = (1/2) (30 kg) (20 m/s)²
= (1/2) (30 kg) (400 m²/s²)
= (15 x 400) (kg-m²/s²)
= 6,000 joules .