a. the cost of a call for six minutes is 0.70.
b.the cost of a 14-minute call is 2.62.
c.the cost of a 9 ½2-minute call is 1.66.
<h3>How to find the cost of each call ?</h3>
given that
rate schedule for an m-minute call from any of its pay phones 0.70.
c(m) = 0.70 when m<=6
c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer
c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.
a. to find the cost of a call for six minutes.
already given that c(m) =0.70 when m=6.
Therefore, the cost of a call for six minutes is 0.70.
b. to find the cost of a 14-minute call.
according to given information

Therefore,the cost of a 14-minute call is 2.62.
c.to find the cost of a 9 ½2-minute call
according to given information

Therefore,the cost of a 9 ½2-minute call is 1.66.
Learn more about problems on cost of call, refer:
brainly.com/question/16584226
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