Use the Ideal law Equation :

P.V= n.R.T

V = 0.5 L

P = 1.0 atm

R= 0.0821 L*atm/mol*K

n = R*T/P*V

P*V= n*R*T

1.0 * 0.5 = n *0.0821*298

0,5 = n* 24.4658

n = 0,5 / 24.4658

n =0.0204 moles

8 0

3 years ago

How many moles of solute are in 5 liters of a 5 M solution?

yKpoI14uk [10]

500 because you need the

6 0

3 years ago

To make a 1.0L dilute of 0.5M from a stock solution of 12M, how much solution will be needed?

Cerrena [4.2K]

Answer:

$V_{concentrated}=0.042L=4.2mL$

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

$M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}$

Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:

$V_{concentrated}=\frac{M_{diluted}V_{diluted}}{M_{concentrated}} =\frac{0.5M*1.0L}{12M}\\ \\V_{concentrated}=0.042L=4.2mL$

Best regards.

6 0

3 years ago