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eimsori [14]
3 years ago
7

What variables(s) are constant for charler's law?

Chemistry
1 answer:
igomit [66]3 years ago
6 0
Pressure is the constant in Charles' law. If the pressure is constant, then this law upholds as being true.
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Which option can be classified as a pure substance
Zina [86]
I have done this question before and even though you didn’t provide the options. I think the correct option is elements
4 0
4 years ago
Read 2 more answers
In an experiment, a compound was determined to contain 68.94% oxygen and 31.06% of an unknown element by weight. The molecular w
monitta

Answer is: the compound is B₂O₃.

ω(O) = 68.94% ÷ 100%.

ω(O) = 0.6894; percentage of oxygen in the compound.

ω(X) = 31.06% ÷ 100%.

ω(X) = 0.3106; percentage of unknown element in the compound.

If we take 69.7 grams of the compound:

M(compound) = 69.7 g/mol.

n(compound) = 69.7 g ÷ 69.7 g/mol.

n(compound) = 1 mol.

n(O) = (69.7 g · 0.6894) ÷ 16 g/mol.

n(O) = 3 mol.

M(compound) = n(O) · M(O) + n(X) · M(X).

n(X) = 1 mol ⇒ M(X) = 21.7 g/mol; there is no element with this molecular weight.

n(X) = 2 mol ⇒ M(X) = 10.85 g/mol; this element is boron (B).

8 0
3 years ago
PLEASE HELP!!!!!!!!!
andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

5 0
3 years ago
AgNO3(aq)+Cu(s)→Ag(s)+Cu(NO3)2(aq) is an example of which type of reaction?
Elan Coil [88]
Its a displacement reaction
7 0
4 years ago
HELP PLZ!!!
NikAS [45]

Answer:

Approx. 8 grams of KNO3 will not dissolve

Explanation:

According to the curve at 20 degrees C only 32 grams of KNO3 can dissolve in 100 grams of water meaning if you hvae 40 grams of KNO3 in water at 20 degrees C ; 40-32= 8

8 0
3 years ago
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