Answer:
Explanation:
Hello there!
Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
![K=\frac{[NO_2]^2}{[NO]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BNO%5D%5E2%5BO_2%5D%7D)
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:
In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
Best regards!
Well, the molar mass of acetone would be
3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.
out of this total, 3(12.011), or 36.033 grams are carbon
So, to find the percent, you do part over whole
36.033/58.08, which equals 0.6204 with significant figures
multiply that by 100 to get 62.04%
Hope that helps!
2 protons+, 1 neutron, and 2electrons-
Answer:
Explanation:
The first thing we calculate are the moles: (50.0 g)/(20.0063 g/mol) =2.5 moles
Then we use the inverse formula for the molarity: (2.5 mol)/(12.0 M) = 0.208 L
My bad, I pressed the wrong button for answer!
