Question

A 1-kg discus is thrown with a vertical velocity of 19 m/s at an angle of 35 degrees from a height of 1.94 m. Do not factor in air resistance. Calculate the vertical and horizontal velocities.

Answer 1

Answer:

Vertical velocity   $V_y = 10.89 \ m/s$

Horizontal velocity  $V_x = 15.57 \ m/s$

Explanation:

If a 1 -kg is thrown vertically with a velocity of 19  m/s at an angle of 35 °C from a height 1.94 m

The vertical and horizontal component can be resolved as:

$V_y = Vsin \theta \\ \\ \\\\V_x = Vcos \theta$

For Vertical component :

$V_y = V sin \theta \\\\V_y = 19 * sin 35 \\ \\ V_y = 19* 0..5736 \\ \\ V_y = 10.89 \ m/s$

For horizontal velocity

$V_x = V cos \theta \\\\V_x = 19 * cos 35 \\ \\ V_x = 19* 0.8192 \\ \\ V_x = 15.57 \ m/s$