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kondaur [170]
3 years ago
5

A 1-kg discus is thrown with a vertical velocity of 19 m/s at an angle of 35 degrees from a height of 1.94 m. Do not factor in a

ir resistance. Calculate the vertical and horizontal velocities.
Physics
1 answer:
Travka [436]3 years ago
4 0

Answer:

Vertical velocity   V_y = 10.89 \ m/s

Horizontal velocity  V_x = 15.57 \ m/s

Explanation:

If a 1 -kg is thrown vertically with a velocity of 19  m/s at an angle of 35 °C from a height 1.94 m

The vertical and horizontal component can be resolved as:

V_y = Vsin \theta \\ \\ \\\\V_x = Vcos \theta

For Vertical component :

V_y = V sin \theta \\\\V_y  = 19 * sin 35 \\ \\   V_y = 19* 0..5736 \\ \\ V_y = 10.89 \ m/s

For horizontal velocity

V_x = V cos \theta \\\\V_x  = 19 * cos 35 \\ \\   V_x = 19* 0.8192 \\ \\ V_x = 15.57 \ m/s

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