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kondaur [170]
3 years ago
5

A 1-kg discus is thrown with a vertical velocity of 19 m/s at an angle of 35 degrees from a height of 1.94 m. Do not factor in a

ir resistance. Calculate the vertical and horizontal velocities.
Physics
1 answer:
Travka [436]3 years ago
4 0

Answer:

Vertical velocity   V_y = 10.89 \ m/s

Horizontal velocity  V_x = 15.57 \ m/s

Explanation:

If a 1 -kg is thrown vertically with a velocity of 19  m/s at an angle of 35 °C from a height 1.94 m

The vertical and horizontal component can be resolved as:

V_y = Vsin \theta \\ \\ \\\\V_x = Vcos \theta

For Vertical component :

V_y = V sin \theta \\\\V_y  = 19 * sin 35 \\ \\   V_y = 19* 0..5736 \\ \\ V_y = 10.89 \ m/s

For horizontal velocity

V_x = V cos \theta \\\\V_x  = 19 * cos 35 \\ \\   V_x = 19* 0.8192 \\ \\ V_x = 15.57 \ m/s

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lana66690 [7]

Answer: F = 113.4.10^{-3}N

Explanation: Net Force is the total forces acting in an object. In this case, there are two forces acting on the charge: one due to magnetic field (Fm) and another due to electric field (Fe). So, net force is

F = Fe + Fm

Force due to electric field

To determine this force:

Fe = q.E, where q is the charge and E is electric field.

Calculating:

Fe = q.E

Fe = 1.8.10^{-6}.4.6.10^{3}

Fe = 8.28.10^{-3}N

Force due to magnetic field: It can only happens when the charge is in movement, so

Fm = q.(v×B), where v represents velocity and B is magnetic field

The cross product indicates that force is perpendicular to the velocity and the field.

Calculating:

Fm = q.v.B.senθ

As θ=90°,

Fm = q.v.B

Fm =  1.8.10^{-6}.3.1.10^{6}.1.2.10^{-3}

Fm = 6.696.10^{-3}N

F, Fm and Fe make a triangle. So, using Pythagorean theorem:

F = \sqrt{Fe^{2} + Fm^{2} }

F = \sqrt{(8.28.10^{-3} )^{2} +(6.696.10^{-3} )^{2} }

F = 113.4.10^{-3}N

The net force acting on the charge is F = 113.4.10^{-3}N

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kogti [31]

Well, the figure seems to report that velocity is measured in m/s²... That label should say m/s. (Unless of course this is the graph of acceleration over time, but then the answer would probably be more complicated than the given choices.)

If the graph indeed shows velocity, and the unit is just a typo, then the displacement from A to D is equal to the area under the curve.

From A to B, the area is of a triangle with height 4 m/s and base 1 s, hence the area is 1/2 • (4 m/s) • (1 s) = 2 m.

From B to C, it's a rectangle with length 3 s and height 4 m/s, hence with area (3 s) • (4 m/s) = 12 m.

From C to D, it's a trapezoid with "height" 2 s and bases 4 m/s and 2 m/s, hence with area 1/2 • (4 m/s + 2 m/s) • (2 s) = 6 m.

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6 0
3 years ago
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A wooden stick would be best.
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