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erastova [34]
3 years ago
12

Order the speed of sound through these materials from the slowest to the fastest.

Physics
1 answer:
Sholpan [36]3 years ago
8 0

Speed of sound in cold air < Speed of sound in Warm air < Speed of sound in hot molten lead < Speed of sound in water

Explanation:

Step 1:

Speed of sound in water varies from 1450 to 1498 meters per second

Speed of sound in Hot Molten lead is approximately 1210 meters per second

Speed of sound in warm air is approximately 338.89 meters per second

Speed of sound in cold air is approximately 293.33 meters per second

Step 2:

In warm air sound travels faster than that of sound travelling nature in cold air.

∴ Speed of sound in cold air < Speed of sound in Warm air < Speed of sound in hot molten lead < Speed of sound in water

Speed of sound in cold air the slowest while Speed of sound in water is the fastest mean.

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Billy drops a ball from a height of 1 m. The ball bounces back to a height of 0.8 m, then
Andreas93 [3]

Answer:

The displacement is  \Delta H =    -  1 \ m

The distance  is  D =  4 \  m

Explanation:

From  the question we are told that

    The height from which the ball is dropped is  h  =  1 \ m

    The height attained at  the first bounce is  h_1  = 0.8  \  m

    The height attained at  the second bounce is   h_2 = 0.5 \  m

    The height attained at  the third bounce is h_3 = 0.2 \  m

Note  : When calculating displacement we consider the direction of motion

Generally given that upward is positive  the total displacement of the ball is mathematically represented as

            \Delta H =  (0  -  h ) + ( h_1 - h_1 ) + (h_2 - h_2 )+ (h_3 - h_3)

Here the 0 show that there was no bounce back to the point where Billy released the ball  

           \Delta H =  (0  -  1 ) + ( 0.8- 0.8 ) + (0.5 - 0.5 )+ (0.2 - 0.2)

=>          \Delta H =    -  1 \ m

Generally the distance covered by the ball is mathematically represented as  

                D =  h +  2h_2 + 2h_3 + 2h_3

The 2 shows that the ball traveled the height two times

              D =  1 +  2* 0.8  + 2* 0.5 + 2* 0.2

=>           D =  4 \  m

     

5 0
3 years ago
Strong forces
sdas [7]

Strong forces:

- are forces holding nucleons together

- are independent of electric charge

- act only over a very short distance

So, correct answer is 4) all of these

Explanation:

The strong force is one of the 4 fundamental forces of nature. It is responsible for holding the nucleons (protons and neutrons) together into the nucleus of the atom.

In fact, the protons inside the nucleus of an atom experience a repulsive, electrostatic force between each other: if this force was not balanced, the protons will simply fly away from each other, and the nucleus would break apart, so no nucleus could exist.

The strong force acts to prevent this effect: the strong force is attractive at such short scales, and it holds the protons and the neutrons together. It is independent of the electric charge: in fact, it acts in the same way on protons and neutrons, being attractive in both cases. Also, the strong force acts only over very short distances, so it acts only inside the nucleus of an atom.

Therefore, all the statements are correct, so the correct option is

4) all of these

#LearnwithBrainly

6 0
3 years ago
you throw a rock with a horizontal velocity at 36.6 m/s out a window that is 29.5 m above the ground. What was it’s total time i
ANEK [815]
29.5-4.9x^2= your answer
4 0
3 years ago
the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco
dem82 [27]

Answer:

<em>Time =  5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

v_f=v_o+a.t

And the distance s is

\displaystyle s=v_o.t+\frac{gt^2}{2}

Given the object starts from rest, vo=0 and vf=20 m/s at a=4\ m/s^2. We compute t

\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}

\boxed{t=5\ sec}

Now we compute s

\displaystyle s=0+\frac{4\times 5^2}{2}

\boxed{s=50\ m}

5 0
3 years ago
The higher the voltage across a bulb the b__________ it is.
podryga [215]

Answer:

Brighter

Explanation:

8 0
3 years ago
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