How to play 10 fingers claw on pubg mobiles?
2 answers:
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Answer:
Volume,
Explanation:
Given that,
The diameter of a human cell is 11 μm
It is enclosed by a membrane that is 4,4 nm thick.
We need to find the volume of the cell. The cell is spherical in shape. The volume of a sphere is given by the formula as follows :
r is the radius of the sphere, r = 5.5 μm
So,
So, the volume of the cell is .
1. B
It comes from Newton's law of universal gravitation.
<span><span>,
</span></span>
<span><span>
</span></span>
Where:
F is the force between the masses, (the one we are looking for)G is the gravitational constant,m1 is the first mass (Earth)m2 is the second mass (sattelite)r is the distance between the centers of the masses.As you can see except for m2, all other values are the same.
If mass is bigger the force grows.
2. D.
Again check the formula. The bigger distance, the smaller force. So, closer = bigger force.
3.C It will increase.Ohm's law:
Where:
I is the current.
V is voltage
R is the resistance.
In order for current to remain the same, while voltage increases, the resistance has to increase accordingly.
It comes from Newton's law of universal gravitation.
<span><span>,
</span></span>
</span></span>
Where:
F is the force between the masses, (the one we are looking for)G is the gravitational constant,m1 is the first mass (Earth)m2 is the second mass (sattelite)r is the distance between the centers of the masses.As you can see except for m2, all other values are the same.
If mass is bigger the force grows.
2. D.
Again check the formula. The bigger distance, the smaller force. So, closer = bigger force.
3.C It will increase.Ohm's law:
Where:
I is the current.
V is voltage
R is the resistance.
In order for current to remain the same, while voltage increases, the resistance has to increase accordingly.
Answer:
t = 1023.9 seconds
Explanation:
Given that,
The average velocity of a Mustang, v = 33m/s
Distance, d = 21 miles = 33789 m
Let the driver takes t seconds. So,
Speed = distance/time
So, it will take 1023.9 seconds to complete the course.