The wavelength of light is
given as 463 nm or can also be written as 463 x 10^-9 m. [wavelength = ʎ]
We know that the speed of
light is 299 792 458 m / s or approximately 3 x 10^8 m / s. [speed of
light = c]
Given the two values, we can calculate
for the frequence (f) using the formula:
f = c / ʎ
Substituting the given
values:
f = (3 x 10^8 m / s) / 463 x
10^-9 m
f = 6.48 x 10^14 / s = 6.48 x
10^14 s^-1
<span>f = 6.48 x 10^14 Hz</span>
Answer:
A) 31 kJ
B) 1.92 KJ
C) 40 , 2.48
Explanation:
weight of person ( m ) = 79 kg
height of jump ( h ) = 0.510 m
Compression of joint material ( d ) = 1.30 cm ≈ 0.013 m
A) calculate the force
Fd = mgh
F = mgh / d
W = mg
F(net) = W + F = mg ( 1 + ![\frac{h}{d} )](https://tex.z-dn.net/?f=%5Cfrac%7Bh%7D%7Bd%7D%20%29)
= 79 * 9.81 ( 1 + (0.51 / 0.013) )
= 774.99 ( 40.231 ) ≈ 31 KJ
B) calculate the force when the stopping distance = 0.345 m
d = 0.345 m
Fd = mgh hence F = mgh / d
F(net) = W + F = mg ( 1 + ![\frac{h}{d} )](https://tex.z-dn.net/?f=%5Cfrac%7Bh%7D%7Bd%7D%20%29)
= 79 * 9.81 ( 1 + (0.51 / 0.345) )
= 774.99 ( 2.478 ) = 1.92 KJ
C) Ratio of force in part a with weight of person
= 31000 / ( 79 * 9.81 ) = 31000 / 774.99 = 40
Ratio of force in part b with weight of person
= 1920 / 774.99 = 2.48
Answer:
I think its 9.0397 Ohms
Explanation:
take the reciprocal of all the resistances: 1/15, 1/65, 1/35
then add them: = 151/1365
then reciprocal the answer: =1365/151
And chuck it on a calculator: =9.04 Ohms
I think this is right but I'm not entirely sure. Tell me if I'm right by the way!
Answer:
Energy = 7.83 x 10⁻¹⁹ J
Energy = 6.63 x 10⁻¹⁹ J
Explanation:
The energy of a photon in terms of wavelength can be calculated by the following formula:
![Energy = \frac{hc}{\lambda}\\](https://tex.z-dn.net/?f=Energy%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D%5C%5C)
where,
h = Plank's Constant = 6.63 x 10⁻³⁴ Js
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
Now, for λ = 254 nm = 2.54 x 10⁻⁷ m:
![Energy = \frac{(6.63\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{2.54\ x\ 10^{-7}\ m}\\](https://tex.z-dn.net/?f=Energy%20%3D%20%5Cfrac%7B%286.63%5C%20x%5C%2010%5E%7B-34%7D%5C%20Js%29%283%5C%20x%5C%2010%5E8%5C%20m%2Fs%29%7D%7B2.54%5C%20x%5C%2010%5E%7B-7%7D%5C%20m%7D%5C%5C)
<u>Energy = 7.83 x 10⁻¹⁹ J</u>
<u></u>
Now, for λ = 300 nm = 3 x 10⁻⁷ m:
![Energy = \frac{(6.63\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{3\ x\ 10^{-7}\ m}\\](https://tex.z-dn.net/?f=Energy%20%3D%20%5Cfrac%7B%286.63%5C%20x%5C%2010%5E%7B-34%7D%5C%20Js%29%283%5C%20x%5C%2010%5E8%5C%20m%2Fs%29%7D%7B3%5C%20x%5C%2010%5E%7B-7%7D%5C%20m%7D%5C%5C)
<u>Energy = 6.63 x 10⁻¹⁹ J</u>
Answer:
B
Explanation:
Protons have a positive electrical charge of +1,
Electrons have a negative charge of -1,
Neutrons have a neutral charge of about 0.