Because real electrons are in an electron cloud, not layers
Answer:
A car covers distance of 291.2 m if the car is travelled at<em> speed of 56 m/s in 5200 milliseconds.
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<u>Explanation:
</u>
To find the distance covered by the car we use the the relationship between speed, time and distance is . Given, speed = 56 m/s and time = 5200 milliseconds. Covert milliseconds into seconds we can get by dividing it with 1000 = = 5.2 seconds.
Now,
Thus a car can travel 291.2 m if the car is travelled at speed of <em>56 m/s in 5200 milliseconds.
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Newton's second law is:
F=m*a,
where a=dv/dt, so
F=m*(dv/dt)
Rearranging gives:
F*dt=m*dv.
Basic integration gives:
F*t=m(vf-v0),
where vf and v0 are the final and initial velocities of the object respectively.
In your case vf=0, because the ball stops completely, and v0=10m/s.
Rearranging the last expression gives F=(m(vf-vo))/t.
Plug in numbers to find F=(2*10)/0.03=666.6 N
Answer:
1 x 10¹²J
Explanation:
Given parameters:
Mass of the water pumped = 2.05 x 10⁸kg
Height = 500m
Unknown:
Potential energy = ?
Solution:
The potential energy amassed by water at this height is expressed as;
P.E = mgH
m is the mass
g is the acceleration due to gravity
H is the height
Insert the parameters and solve;
P.E = 2.05 x 10⁸ x 9.8 x 500 = 1 x 10¹²J
Answer:
The correct answer is d d= 30 m
Explanation:
The electric force is given by
Fe = q E
Since the particle charge is negative, the force and acceleration oppose the movement, let's use Newton's second law
F = m a
q E = m a
a = q E / m
Let's reduce
q = -5.0 mC = -5.0 10⁻⁶ C
m = 20 mg = 20 10⁻³ g (1kg / 1000 g) = 20 10⁻⁶ kg
a = - 5.0 10⁻⁶ 60/20 10⁻⁶
a = -15 m / s²
Now we can use kinematics
v² = v₀² + 2 a d
At the point where stop (v=0)
0 = v₀² + 2 a d
d = - v₀² / 2 a
d = 30² / (2 -(15))
d = 30 m
The correct answer is d