Question

If the volume occupied by the air in a bicycle pump is 525 cm3, and the pressure changes from 73.2 kPa to 122.5 k.Pa as the piston is pushed down, what is the new volume occupied by the air?

Answer 1

Answer:

$V_2=313.71\ cm^3$

Explanation:

Given that,

Initial volume, $V_1=525\ cm^3$

The pressure changes from 73.2 kPa to 122.5 k.Pa.

We need to find the new volume occupied by the air. Let it is V₂. It can be calculated using Boyle's law such that,

$P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{73.2\times 525}{122.5}\\\\V_2=313.71\ cm^3$

So, the new volume is $313.71\ cm^3$.