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olya-2409 [2.1K]
3 years ago
8

To run a thin layer chromatography experiment with a chemical substance, begin by marking a horizontal line near the bottom of a

TLC plate with_______. Place a_______spot of the substance onto the line. For the mobile phase, add a small amount of _______ at the bottom of a TLC chamber. Place the plate in, then_______the chamber. Once the mobile phase approaches the top of the plate, remove the plate and mark the _______ line. Note the position of the spots and calculate Rf values if needed.
Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

TLC is thin-layer chromatography, a chromatography technique which is used for separating the non-volatile mixtures.

Explanation:

To run a thin layer thin layer chromatography experiment with a chemical substance, begin by marking a horizontal line near the bottom of TLC plate with PENCIL. Place a SMALL spot of the substance onto the line. For the mobile phase add a small amount of SOLVENT at the bottom of TLC chamber. Place the plate in, then COVER the chamber. Once the mobile phase approaches the top of the plate, remove the plate and mark the SOLVENT line. Note the positions of the spot and calculate the Rf if needed.

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The overall cell reaction occurring in an alkaline battery isZn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s) (e) In practice, vol
zubka84 [21]

b) Mass of MnO₂ = 5.981 g

    Mass of H₂O = 1.2384 g

c) Total Mass of Reactant consumed = 11.708 g

b) Given Reaction

            Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)

  Mass of Zn = 4.50 g

  Moles of Zn = 0.0688 moles

   Now,

    Moles of Zn = moles of MnO₂ = moles of H₂O = moles of ZnO = moles of                   Mn(OH)₂

Hence ,

Moles of MnO₂ = 0.0688 moles

Mass of MnO₂ = 0.0688 × 86.9368 g

                        = 5.981 g

Similarly,

    Moles of H₂O = 0.0688 moles

     Mass of H₂O = 0.0688 × 18 g

                           = 1.2384 g

c) now ,

    Moles of  ZnO = 0.0688 moles

     Mass of  ZnO  = 0.06880× 81.3794 g

                              = 5.598 g

 Moles of  Mn(OH)₂ = 0.0688 moles

  Mass of  Mn(OH)₂ =0.0688 × 88.952 g

                                  = 6.11 g

Total mass of Product = 11.708 g

Total Mass of Reactant = 11.715 g

Hence,

    Total mass of reactant consumed = 11.708 g

c)  As total mass of reactant is more than that of mass of reactant consumed , Hence G is more than that of mass of reactant consumed .

G = - nFEcell

 

and no. of moles of reactant  is greater than that of number of moles of reactant consumed .

       Hence voltaic cell of given Capacity are heavier than that of mass of reactant consumed .

 Thus from above conclusion we can say that , Mass of the reactant consumed is 11.708 g.

Learn more about Galvanic Cell here : brainly.com/question/19340007

#SPJ4

3 0
2 years ago
What two types of matter are closest in<br> density? How do you know?<br> ings.
maks197457 [2]

Answer:

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Answer:

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Answer:

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Explanation:

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Fiesta28 [93]

Answer:

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Explanation:

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