Answer:
Al4C3 + 12H2O = 3CH4 + 4Al(OH)3
Explanation:
Not sure if any explanation is needed but always start with the most complex compound. In this case it is Al(OH)3. You can see that there is 4 Aluminiums on the other side so I would start by putting a 4 next to the Al(OH)3. This now gives me 12 Hydrogens and 12 Oxygens on the right side. I put a 3 next to the CH4 to balance the Carbons on the left side. This leaves me with 12 Oxygens and 24 Hydrogens on the right side. This ends up being perfect because I can put a 12 next to the H2O.
Answer:
its not c or d because we know nothing will happen to the bow- so its up to a and b- making the answer b :V
Explanation:
D. quantitative properties
Boiling point and freezing point depression are both values that can be represented quantitatively (in number form).
Answer:
The new volume will be 3.67 L.
Explanation:
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:
"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
P*V=k
Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1 * V1 = P2 * V2
In this case:
- P1= 1.85 atm
- V1= 4.64 L
- P2= 2.34 atm
- V2= ?
Replacing:
1.85 atm* 4.64 L= 2.34 atm* V2
Solving:

V2= 3.67 L
<u><em>The new volume will be 3.67 L.</em></u>