KE=1/2m v2= 1/2 (3kg) (2m/s)2 = 6J (6joules)
The amount of sunlight received per square centimeter is different by 36 times less.
<h3>What is the speed of light?</h3>
A fundamental physical constant, typically abbreviated as c, the speed of light in a vacuum is significant in many branches of physics. 299792458 metres per second, or around 300000 kilometres per hour or 186,000 miles per hour, is the precise figure. The special theory of relativity states that the maximum speed at which ordinary matter, energy, or any signal containing information may move across space is given by the constant c.
Visible light is an example of electromagnetic radiation that moves at the speed of light. Light and other electromagnetic waves appear to move instantly for many practical uses, but their limited speed has dramatic implications over vast distances and particularly sensitive measurements. The starlight that can be seen from Earth has been out there for a very long time, allowing people to see far-off objects and learn about the evolution of the cosmos. It can take minutes to hours for signals to reach from Earth to a spacecraft when corresponding with far-off space missions. The absolute shortest communication latency between computers, to computer memory, and within a CPU is fixed in computing at the speed of light.
to learn more about speed of light go to - brainly.com/question/104425
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To calculate for the average speed, we simply divide the total distance covered by the time it takes to travel that distance. In this case, we simply divide 7.5 km with 45 min. Therefore, the skier's average speed is 0.1667 km/min. Hope this helps.
Answer:
K = G Mm / 9R
Explanation:
Expression for escape velocity V_e = 
Kinetic energy at the surface = 1/2 m V_e ²
= 1/2 x m x 2GM/R
GMm/R
Potential energy at the surface
= - GMm/R
Total energy = 0
At height 9R ( 8R from the surface )
potential energy
= - G Mm / 9R
Kinetic energy = K
Total energy will be zero according to law of conservation of mechanical energy
so
K - G Mm / 9R = 0
K = G Mm / 9R
Answer:
+1.46×10¯⁶ C
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C
Force (F) = 0.615 N
Distance apart (r) = 0.750 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Charge 2 (q₂) =?
The value of the second charge can be obtained as follow:
F = Kq₁q₂ / r²
0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²
0.615 = 236700 × q₂ / 0.5625
Cross multiply
236700 × q₂ = 0.615 × 0.5625
Divide both side by 236700
q₂ = (0.615 × 0.5625) / 236700
q₂ = +1.46×10¯⁶ C
NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C
