The heat of fusion must be approx from 0 to infinity
Answer:
A
Explanation:
R=V/I
IF you double the resistance, it's become:
2R=(1/2)I
(A) power = 0.208 kW = 208 watts
(B) energy = 6.6 x 10^{9} joules
Explanation:
energy consumed per day = 5 kWh
(a) find the power consumed in a day
1 day = 24 hours
power = \frac{energy}{time}
power = \frac{5}{24}
power = 0.208 kW = 208 watts
(b) find the energy consumed in a year
assuming it is not a leap year and number of days = 365 days
1 year = 365 x 24 x 60 x 60 = 31,536,000 seconds
energy = power x time
energy = 208 x 31,536,000
energy = 6.6 x 10^{9} joules
Answer:
Explanation:
Heat required to raise the temperature
= mass x specific heat x rise in temperature
= .34 x 4200 x ( 95 - 23 )
= 102816 J .
1 kWh = 1000 x 60 x 60 J
= 3600000 J
102816 J = 102816 / 3600000
= .02856 kWh .
