All objects in the universe radiate some form of energy. a. True b. False

2 answers:

5 0

True . but also depends on which kind of object because if you have metal it will not really form energy in my opinion it will just attract another object.

hope i helped

Harrizon [31]3 years ago

3 0

That's true. The only way to stop an object from radiating energy
is to cool it to absolute zero. Since the temperature of space is
roughly 3 degrees above absolute zero, the atoms or molecules
of every object have some kinetic energy, and the object radiates
some heat.

Of course it also absorbs heat at the same time, mostly from the
huge number of stars shining on it.

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In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w

Daniel [21]

Answer:

$v_2=-133.17m/s$ , the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before ( $p_i$ ) and after ( $p_f$ ) the explosion. We will take the east direction as positive.

Before the explosion we have $p_i=m_iv_i=Mv_i$ .

After the explosion we have pieces 1 and 2, so $p_f=m_1v_1+m_2v_2$ .

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

$Mv_i=m_1v_1+m_2v_2$

Which means (since we want $v_2$ and $M=m_1+m_2$ ):

$v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}$

So for our values we have:

$v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s$

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3 years ago

Why is it important that a finger be wet<br> before it is touched to a hot clothes iron?

AleksandrR [38]

Why is it important that your finger be wet if you intend to touch it briefly to a hot clothes iron to test its temperature. If your finger is wet, some of the heat transmitted to your finger will be given to the water which has a high specific heat capacity and also a larger latent heat of vaporization.

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Arisa [49]

C it is uniformly thick

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