1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rom4ik [11]
3 years ago
8

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Chemistry
2 answers:
marin [14]3 years ago
7 0
<span>The number of molecules of each gas must be equal since 1 mol of any gas needs to contain 6.02x10^23 molecules. So 1mol O</span>₂ and 1mol CO both need to contain 6.02x10^23 molecules
4vir4ik [10]3 years ago
7 0

Answer : Option C) The number of molecules.

Explanation : When comparing 1 mol of oxygen gas with 1 mol of carbon monoxide the number of molecules must be same. Each mole should contains 6.023 X 10^{23} atoms in it. Irrespective of the weight or atomic number avogadro's number remains constant for every mole of atom.

It is a number which is usually given for atoms or molecules, that are contained in the amount of substance given by one mole.

It is denoted by N_{A}.

The units of Avogadro's number can be expressed in terms of electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.

You might be interested in
Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet
sergeinik [125]

Volume of room  = 7.2 m \times 5.8 m \times  3.9 m

= 162.864 m^{3}

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg  = 6,400 \times 1000

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone  = \frac{6,400,000 microgram}{162.864 m^{3}}

= 39296.5910 microgram per cubic meter or 3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}

Hence, concentration of acetone is equal to 4.0\times 10^{4} \mu g/m^{3}

7 0
3 years ago
Which of these liquids are solutions? Check all that apply.
andrey2020 [161]
Salt watersodaorange juice<span>coffee</span>
4 0
3 years ago
Read 2 more answers
1. How many moles are in 3.4 x 1024 molecules of HCl?
pochemuha

1. How many moles are in 3.4 x 10²⁴ molecules of HCl?

if there are 6.022 × 10²³ molecules in 1 mole of HCl

then there are 3.4 × 10²⁴ molecules in X moles of HCl

X = (3.4 x 10²⁴ × 1) / 6.022 × 10²³ = 5.6 moles of HCl

2. How many grams are in 2.59 x 10²³ formula units of Al₂O₃?

 if there are 6.022 × 10²³ units in 1 mole of Al₂O₃

then there are 2.59 × 10²³ units in X moles of Al₂O₃

X = (2.59 x 10²³ × 1) / 6.022 × 10²³ = 0.43 moles of Al₂O₃

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of Al₂O₃ = 0.43 × 102 = 43.86 g

3. How many grams are in 9.05 x 1023 atoms of silicon?

if there are 6.022 × 10²³ atoms in 1 mole of silicon

then there are 9.05 × 10²³ atoms in X moles of silicon

X = (9.05 x 10²³ × 1) / 6.022 × 10²³ = 1.5 moles of silicon

mass = number of moles × molecular weight

mass of silicon = 1.5 × 28 = 42 g

4. If you had 7.00 moles of PtO₂, how many grams would you have?

mass = number of moles × molecular weight

mass of PtO₂ = 7 × 227 = 1589 g

5. How many moles are in 29.2 L of oxygen gas at STP?

At standard temperature and pressure (STP) we may use the  following formula:

number of moles = volume (L) / 22.4 (L / mol)

number of moles of oxygen = 29.2 / 22.4 = 1.3

6. What is the volume (liters) of 75.8 g of N₂ at STP?

number of moles = mass / molecular weight

number of moles of N₂ = 75.8 / 28 = 2.7 moles

At standard temperature and pressure (STP) we may use the  following formula:

number of moles = volume (L) / 22.4 (L / mol)

volume = number of moles × 22.4

volume of N₂ = 2.7 × 22.4 = 60.48 L

4 0
4 years ago
How many moles of nitrogen gas are present in a 28.9 dm3 temperature of 55.0 °C and a pressure of 144 kPa?
jeka57 [31]

Given :

Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .

Volume of container, V = 28.9 dm³ = 0.0289 m³ .

Pressure, P = 144 kPa = 144000 Pa .

To Find :

Number of moles of nitrogen  gas.

Solution :

We know, by ideal gas equation :

PV = nRT  ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .

n = \dfrac{PV}{RT}\\\\n = \dfrac{144000\times 0.0289}{8.31 \times 328} \ moles\\\\n = \dfrac{4161.6}{2725.68}\\\\n = 1.53 \ moles

Therefore, number of moles of nitrogen gas is 1.53 moles.

8 0
3 years ago
Calculate the theoretical atom economy for each reaction.
Arisa [49]
100% find the gfm of both sides then divide 
4 0
4 years ago
Other questions:
  • How is the ionization energy, E, related to a period of elements?
    5·2 answers
  • Which requirement is essential for any of the chemical process that occur in cells to take place
    9·1 answer
  • Predict the mass of oxygen required to react with 14 g of nitrogen to make N2O5 if 16 g of oxygen reacts with 14 g of nitrogen t
    8·1 answer
  • Ammonia gas and oxygen gas react to form water vapor and nitrogen monoxide gas. What volume of water would be produced by this r
    10·1 answer
  • Why does the temperature decrease when you do an endothermic reaction ?
    12·2 answers
  • An important reaction sequence in the industrial production of nitric acid is the following:
    12·1 answer
  • PLEASEEEE ANSWER ASAP!!!!!!!!!!!!!!!!!
    6·2 answers
  • How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
    9·1 answer
  • Which element has 4 energy levels and 7 valence electrons
    6·1 answer
  • Write the chemical formula for each binary ionic compound
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!