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malfutka [58]
3 years ago
12

Pete has 4 packs of gum balls. Each pack has 5 gum balls. If Pete gives the same number of gum balls to 6 friends, how many gum

balls will each friend get?
Mathematics
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

3 1/3 gum balls per friend

Step-by-step explanation:

Packs of gum balls Pete has = 4

Each pack = 5 gum balls

Total gum balls Pete has = Number of packs of gum balls × Number of gum balls in each pack

= 4 × 5

= 20 gum balls

Pete gives the same number of gum balls to 6 friends.

Each friend gets = Total gum balls / number of friends

= 20 gum balls / 6 friends

= 3 2/6 gum balls per friend

= 3 1/3 gum balls per friend

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\bf y=\cfrac{1}{2}(x-7)(x-7)

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so, when x = 7, y = 0, that's the x-intercept, or so-called a solution or zeros.

now, it happens twice though, so, that simply means, the root of 7 has a multiplicity of 2  and is an even multiplicity, and even number, and when that happens, the graph doesn't really cross the x-axis, it simply bounces off of it.

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8 0
3 years ago
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erastova [34]

Answer : 4 times

Here it's given that ,

  • The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .

And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .

Let us take ,

  • base of blue butterfly be b
  • height of blue butterfly be h
  • Area be A .

Then ,

  • base of red butterfly will be 2b .
  • height of red butterfly will be 2h .
  • Area be A' .

We know that ,

→ area of the triangle = 1/2 × base × height

So that ,

→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)

→ A/A' = bh/4bh

→ A/A' = 1/4

→ A' = 4A

<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>

I hope this helps.

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2 years ago
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